Answer: I think the answer is 88.5%
Step-by-step explanation:
Subtract 9 twice.
24-9-9 = 6
Half of 6 is 3, so 3 is the width since adding it twice and adding the length twice gives perimeter.
The hexagon divides the circle into 6 parts. That means the angle projecting each side is: 360°÷ 6 = 60°
The area of a circle is: πr²
78.54 in² divided by pi is 25 making the radius = 5
I would then use SOH CAH TOA to solve for the side.. knowing the hypotenuse is the radius and the angle to split it into a right triangle is 30°
Sin(30) = s/5
5*Sin(30) = s
12*s = perimeter hexagon
(remember s is half the hexagon side)
12*5*Sin(30) = perimeter hexagon
30 inches = perimeter
Explanation:
Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that
a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.
Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.
Answer:
3.95 and -3.95
Step-by-step explanation:
To graph a circle you can use the formula or (x – h)^2 + (y – k)^2 = r^2. So substituting in the given, we get x^2+y^2=49/pi. The x intercept is when y=0. So x^2=49/pi and so
x = sqrt(49/pi) and rounding to the nearest tenth, we get 3.95 and -3.95 because it isn’t a principal square root.