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3 years ago

HELPO ASAPPPPPP!!!!!!!!!!!-

Mathematics

2 answers:

Jlenok [28]3 years ago

4 0

Step1) divide 1st term by the 1st term

so, 5x divide by 5x^3 which is x^2

step2) distribute to ALL terms

then multiply 4 (your 2nd term) by the x^2 (quotient)

step3) subtract

so the 5x^3 you get from 5x and x^2 is positive... you subtract it from the 5x^3 inside. And your result from distribution should be 4x^2 which you subtract

step4) repeat

and u continue that all the way through!

vfiekz [6]3 years ago

3 0

Answer:

The anser is X^2 - 7x - 5

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Use a quadratic equation to find two real numbers with a sum of -43 and a product of 306.

vlabodo [156]

Answer:

Real numbers = 39 and 9

Step-by-step explanation:

The standard form of a quadratic equation is ax² + bx + c = 0

Given the following data;

a = 1

b = -43

c = 306

Quadratic equation formula is;

$x = \frac {-b \; \pm \sqrt {b^{2} - 4ac}}{2a}$

Substituting into the equation, we have;

$x = \frac {-(-43) \; \pm \sqrt {43^{2} - 4*1*306}}{2*1}$

$x = \frac {43 \pm \sqrt {1849 - 1224}}{2}$

$x = \frac {43 \pm \sqrt {625}}{2}$

$x = \frac {43 \pm 25}{2}$

$x_{1} = \frac {43 + 25}{2}$

$x_{1} = \frac {68}{2}$

$x_{1} = 39$

$x_{2} = \frac {43 - 25}{2}$

$x_{2} = \frac {18}{2}$

$x_{2} = 9$

Therefore, the two real numbers are 39 and 9.

The quadratic equation now becomes;

x² - 43x + 306 = (x - 39)(x - 9) = 0

4 0

2 years ago

What is the probability of getting either a sum of 6 or at least one 5 in the roll of a pair of dice

Gekata [30.6K]

In percentage you mean?

3 0

3 years ago

1,000 grams

stiv31 [10]

Answer:

Step-by-step explanation:

A Kilogram (kilo) is a unit of measuring metric mass. To perform this conversion you need to note that

1 Kilogram (kg) = 1000 grams

Which means that <em>converting Kilogram to Grams </em>would involve multiplying kilogram by 1000.

For example, 100 kg to grams = 100 * 1000 = 100,000 Grams

8 0

3 years ago

The side length of a cube is √7 cm. What is the volume of the cube? (Volume = length times width times height)

svlad2 [7]

$\sqrt{7} * \sqrt{7}* \sqrt{7}

=

 \sqrt{7*7*7}

=

 \sqrt{343}$

or

$7 \sqrt{7}$

6 0

3 years ago

Read 2 more answers

What is the perimeter of ABC with vertices at A (-11,4) B(-7,8) and C (-4,4)

Alborosie

Answer:

Step-by-step explanation:

Using the distance formula,

$AB=\sqrt{(-11-(-7))^{2}+(4-8)^{2}}=\sqrt{16+16}=4\sqrt{2}\\AC=\sqrt{(-11-(-4))^{2}+(4-4)^{2}}=7\\BC=\sqrt{(-7-(-5))^{2}+(8-4)^{2}}=\sqrt{4+16}=2\sqrt{5}\\\\$

So the perimeter is $4\sqrt{2}+7+2\sqrt{5}$

3 0

2 years ago