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3 years ago

HELPO ASAPPPPPP!!!!!!!!!!!-

Mathematics

2 answers:

Jlenok [28]3 years ago

4 0

Step1) divide 1st term by the 1st term

so, 5x divide by 5x^3 which is x^2

step2) distribute to ALL terms

then multiply 4 (your 2nd term) by the x^2 (quotient)

step3) subtract

so the 5x^3 you get from 5x and x^2 is positive... you subtract it from the 5x^3 inside. And your result from distribution should be 4x^2 which you subtract

step4) repeat

and u continue that all the way through!

vfiekz [6]3 years ago

3 0

Answer:

The anser is X^2 - 7x - 5

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3 years ago

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3 years ago

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2 years ago

A closed can, in a shape of a circular, is to contain 500cm^3 of liquid when full. The cylinder, radius r cm and height h cm, is

Gemiola [76]

To express the height as a function of the volume and the radius, we are going to use the volume formula for a cylinder: $V= \pi r^2h$
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We know for our problem that the cylindrical can is to contain 500cm^3 when full, so the volume of our cylinder is 500cm^3. In other words: $V=500cm^3$ . We also know that the radius is r cm and height is h cm, so $r=rcm$ and $h=hcm$ . Lets replace the values in our formula:
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Next, we are going to use the formula for the area of a cylinder: $A=2 \pi rh+2 \pi r^2$
where
$A$ is the area
$r$ is the radius
$h$ is the height

We know from our previous calculation that $h= \frac{500}{ \pi r^2}$ , so lets replace that value in our area formula:
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By the commutative property of addition, we can conclude that:
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3 years ago

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andriy [413]

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