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otez555 [7]
3 years ago
12

I need help on #3, #4,5,6

Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0
It may be 

3.
10x+5y

5(2x)+5(y)

4.
20x-15

5.
-6f-11
6.
-24w+12x


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Prove that the value of the expression does not depend on a:<br><br> a−(6a−(5a−8))
djyliett [7]

Step-by-step explanation:

a−(6a−(5a−8))

a-(6a-5a+8)

a-6a+5a-8

6a-6a-8

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so the answer doesn't depend on a

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3 years ago
Three streets intersect to form a right triangle as shown below. The parts of streets that make up the legs of this triangle are
Burka [1]

Answer:

70 yd.

Step-by-step explanation:

The three streets at the intersection form a right triangle.

For a right triangle, the length of the longest side (called hypothenuse) is given by Pythagorean's theorem:

h=\sqrt{x^2+y^2}

where

x is the length of the 1st side

y is the length of the 2nd side

h is the length of the hypothenuse

Here we want to find the hypothenuse.

We have:

x = 42 yd (length of the 1st side)

y = 56 yd (length of the 2nd side)

Substituting, we find h:

h=\sqrt{42^2+56^2}=70 yd

7 0
3 years ago
Assume that y varies directly with x. If y=2/5 when x=1/3, find y when x=1/4. Enter in any fractions using a / (e.g. "1/2" is th
Oxana [17]

x=3/15 thus y=6/15 If x=1/4 then y =2/4

7 0
3 years ago
Help 123456 please help please
uysha [10]
Number 3 is 7

Number 4 is 3

And number 6 is 9

Im sorry I dont know the rest.

I hope this helps.
4 0
3 years ago
1. What is the slope of a line that is perpendicular to the x-axis ​
Ket [755]

Answer:

The slope of a line that is perpendicular to the x-axis ​is undefined.

Step-by-step explanation:

We know that the x-axis is a horizontal line.

  • We also know a line that is perpendicular to the x-axis ​is basically a vertical line.
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Therefore, the slope of a line that is perpendicular to the x-axis ​is undefined.

For example, the slope between (1, 2) and (1, 4) is:

Using the slope formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

                 = [4 - 2] / [1 - 1]

                  = 2 / 0

                  = ∞

8 0
3 years ago
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