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Kipish [7]
3 years ago
12

How do you find a polynomial and factor it completely?

Mathematics
1 answer:
natulia [17]3 years ago
6 0

a² + 10a + 16

Find two numbers whose product equals 16 and sum equals 10:

<u>Product = 16</u>               <u>Sum = 10</u>

    1 * 16                     1 + 16 = 17      <em>doesn't work</em>

    2 * 8                     2 + 8 = 10      THIS WORKS!

    4 * 4                      4 + 4 = 8      <em>doesn't work</em>

Since 2 & 8 satisfy our requirements, those are the values that go into the parentheses.

Answer: (a + 2)(a + 8)

Note: when there is a coefficient for a², a different method is used to find the factors.

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How do you do y=-1/2x+7<br> 5x-2y=10​
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A pathologist has been studying the frequency of bacterial colonies within the field of a microscope using samples of throat cul
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Answer:

P(0) = 0.055

P(1) = 0.16

P(2) = 0.231

P(3) = 0.224

P(4) = 0.162

P(5 or more) = 0.168

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Here λ = 2.90 is the average number of bacteria colonies per field.

This means that \mu = 2.90

Compute P(r) for r = 0, 1, 2, 3, 4, and 5 or more.

P(0) = \frac{e^{-2.9}*(2.9)^{0}}{(0)!} = 0.055

P(1) = \frac{e^{-2.9}*(2.9)^{1}}{(1)!} = 0.16

P(2) = \frac{e^{-2.9}*(2.9)^{2}}{(2)!} = 0.231

P(3) = \frac{e^{-2.9}*(2.9)^{3}}{(3)!} = 0.224

P(4) = \frac{e^{-2.9}*(2.9)^{4}}{(4)!} = 0.162

5 or more:

This is

P(X \geq 5) - 1 - P(X < 5)

In which:

P(X < 5)  = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.055 + 0.16 + 0.231 + 0.224 + 0.162 = 0.832

P(X \geq 5) - 1 - P(X < 5) = 1 - 0.832 = 0.168

So

P(5 or more) = 0.168

7 0
3 years ago
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