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dimulka [17.4K]
3 years ago
8

Which rule represents the transformation shown in the graph?

Mathematics
1 answer:
Oduvanchick [21]3 years ago
3 0

D (x, y) ---> (x, -y)


We can look at Point X and Point X'.


Point X is at (2, -2), and Point X' is at (2, 2).


The y-value has been multiplied by -1, or turned positive, so the answer would be D.

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2. The second term of an arithmetic sequence is -5, and the third term is 12. What is the first term?​
kondaur [170]

Answer: -12

Step-by-step explanation:

To get from -5 to 12, you'd add 7

So to get to the first, subtract 7 from -5

4 0
3 years ago
Find the zeros of the function (x+3)^2(x-5)^6 and state the multiplicity
nikklg [1K]
Find the zeros<span> of Function (</span>x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6<span> = 0=> </span>x--5<span>= 0 => </span>x<span> = </span>5<span>. Therefore real </span>zero's of the function<span> are --</span>3<span>,5.</span><span />
3 0
4 years ago
3.3x10^9+2.6x10^9+7.7x10^8
Tcecarenko [31]
6000000008. Hope this helps
5 0
3 years ago
19/10 into a mixed or whole number?? How would you work this out? i need help.
azamat

10 out of 10 equals 1.

then there is 9 left.

This gives 1 and 9 over 10.

9 over ten is not a whole number as 10 over ten is.

Hope this helps.


5 0
3 years ago
Read 2 more answers
One endpoint of a line segment has the coordinates (-5, 12). If the midpoint of the segment is at (2,9), find the
scoray [572]

Answer:

(9, 6)

Step-by-step explanation:

<u>Midpoint formula is:</u>

  • x = (x₁ + x₂)/2
  • y = (y₁ + y₂)/2

<u>Having coordinates of one end- and midpoint </u>(-5, 12) <u>and</u> (2, 9)<u>:</u>

  • x₁ = -5, y₁ = 12
  • x = 2, y = 9

<u>we get the coordinates of the missing endpoint with coordinates</u> (x₂, y₂):

  • x₂ = 2x - x₁ = 2*2 - (-5) = 4 + 5 = 9
  • y₂ = 2y - y₁ = 2*9 - 12 = 18 - 12 = 6

<u>So the missing point is</u>: (9, 6)

7 0
3 years ago
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