Ok, So:
10x3=30-3=27
It Would Be 27
Answer: tea = 15 rupees per kg
sugar= 3 rupees per kg
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations with the information given:
<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":
</em>
2 t + 3 s =39 (a)
Where:
- t= price of 1 kg of tea
- s = price of 1 kg of sugar
<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30.
"</em>
2(t1.25)+3(s1.2) = 48.30 (b)
- <em>Solving for t in (b)
</em>
2t =39-3s
t = (39 -3s)/2
t = 19.5-1.5s
- <em>Replacing the value of t in (b)
</em>
2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30
2x ( 24.375 -1.875s) +3.6s =48.30
48.75 -3.75s+3.6s= 48.30
48.75-48.30 = 3.75s-3.6s
0.45= 0.15s
0.45/0.15 =s
3 =s
- <em>Replacing the value of s in (a)
</em>
2 t + 3 (3) =39
2 t + 9 =39
2 t =39 -9
2 t =30
t = 30/2
t= 15
Prices in january:
tea = 15 rupees per kg
sugar= 3 rupees per kg
Feel free to ask for more if needed or if you did not understand something.
The answer is A because it is quartile 1 of 4. There are 4 quartiles so logially 1 out of 4 is 25%. Hope this helps!
Answer:b. 0.22
Step-by-step explanation:
Since the lengths of adult walleye fishes are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = lengths of walleye fishes.
µ = mean length
σ = standard deviation
From the information given,
µ = 44 cm
σ = 4 cm
We want to find the probability or fraction of fishes that are greater than 41 cm in length. It is expressed as
P(x > 41) = 1 - P(x ≤ 41)
For x = 41,
z = (41 - 44)/4 = - 0.75
Looking at the normal distribution table, the probability corresponding to the z score is 0.22
