Make use of the inverse sine function. Take the inverse sine of both sides of the equation. Of course, within the appropriate limits, the inverse sine of the sine function is the original argument, as is the case with any inverse function: f⁻¹(f(x)) = x.
... sin⁻¹(sin(x)) = sin⁻¹(-0.5)
... x = sin⁻¹(-0.5)
... x = -30°
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You need to be careful with inverses of trig functions, because they are only defined over a limited domain and range. The range of the inverse sine function is -90° to 90°, so, for example, sin⁻¹(sin(150°)) = sin⁻¹(0.5) = 30°.
Answer:
The cost of renting will be the same for 200 miles.
Step-by-step explanation:
Let n the number of miles and C be the cost. We can represent the cost equations for each companies:
A: C = 12 + 0.09n
B: C = 8 + 0.11n
They want to know when the cost will be the same, so we can set the above 2 equations equal to each other and solve for n:
12 + 0.09n = 8 + 0.11n
0.02n = 4
n = 200
The other numbe rwould be 12 as dad lol brought the answer would be 15
