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choli [55]
3 years ago
12

Vedant received two quotes for new carpet for his home. The quote from Company A is $0.15 less per square foot than the quote fr

om Company B. If Vedant plans to buy 1,200 square feet of carpet, how do his total costs from the two companies compare? Company A is cheaper by $180. Company B is cheaper by $180. Company A is cheaper by $8,000. Company B is cheaper by $8,000.
Mathematics
2 answers:
dezoksy [38]3 years ago
3 0

1200 x 0.15 = 180

 so company a is cheaper by 180 dollars

lisov135 [29]3 years ago
3 0

Answer:

Company A is cheaper by $ 180.

Step-by-step explanation:

Given,

The quote from Company A is $0.15 less per square foot than the quote from Company B,

That is,

Quote from Company B for 1 square foot - quote from Company A for 1 square foot  = $ 0.15

Quote from Company B for 1200 square feet - quote from Company A for 12 square feet = 1200 × 0.15 = $ 180,

Hence, for buying 1,200 square feet of carpet company A is cheaper by $180 than company B.

First option is correct.

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What is the volume of a right circular cone that has a height of 18.8 m and a base with a radius of 19.3 m
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Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

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The volume of the right circular cone is 7,333.32 cubic meters.

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3 years ago
Read 2 more answers
What is question a, b, c, d, e, and f? Thank you!
frosja888 [35]

Step-by-step explanation:

a. f(-4)= 2

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6 0
2 years ago
In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p
skelet666 [1.2K]

Answer:

\mathbf{P(X=5) =0.0888}    

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

\mathtt{P(X=x) =(^{n}_{x} )   \  \pi^x \  (1-\pi)^{n-x}}

\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} )   \  \pi^x \  (1-\pi)^{n-x}}

where;

n = 8 and π = 0.36

For x = 5

The probability \mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} )   \  0.36^5 \  (1-0.36)^{8-5}}

\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} )   \  0.36^5 \  (0.64)^{3}}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =({8 \times 7 } )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =0.0887645}

\mathbf{P(X=5) =0.0888}     to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5)\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})

{P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times  (0.36)^0  \times  (1-0.36)^8  \ )  +  \dfrac{8!}{1!(7!)} \times  (0.36)^1  \times  (1-0.36)^7  \ +\dfrac{8!}{2!(6!)} \times  (0.36)^2  \times  (1-0.36)^6  \ +  \dfrac{8!}{3!(5!)} \times  (0.36)^3  \times  (1-0.36)^5 +  \dfrac{8!}{4!(4!)} \times  (0.36)^4  \times  (1-0.36)^4  \  +  \dfrac{8!}{5!(3!)} \times  (0.36)^5  \times  (1-0.36)^3  \ )

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1  - P( x  ≤ 5 )

P ( x ≥ 6) = 1  - 0.9707

P ( x ≥ 6) = 0.0293

4 0
2 years ago
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