Answer:
BA=BC
Step-by-step explanation:
Answer:

Step-by-step explanation:
The equation of a line in slope-intercept form is
y = mx + b
We need to find the slope, m, and the y-intercept, b.
The line we need is perpendicular to the line 2x + y = 8.
<em>The slopes of perpendicular lines are negative reciprocals.</em>
We solve the given equation for y to find the slope of the given line.
2x + y = 8
y = -2x + 8
The given line has slope -2.
The negative reciprocal of -2 is 1/2.
Our line has slope, m = 1/2.
Now we have
y = 1/2 x + b
Now we use the given point, (-2, 3), for x and y, using x = -2, and y = 3, and we solve for b.
y = 1/2 x + b
3 = 1/2 * (-2) + b
3 = -1 + b
4 = b
b = 4
Now we have
y = 1/2 x + 4
Answer: 
L1: 2x+4y-3=0 ..........(1)
P: (2,0)
The point on the line L1 closest to the given point P is at the intersection of L1 with L2, which is the perpendicular passing through P.
Slope of L1=-2/4=-1/2
Slope of L2=-1/(-1/2)=2
Since it passes throug P(2,0), we can use the point-slope formula:
(y-0)=2(x-2) =>
L2: 2x-y-4=0.............(2)
Solve for x & y using (1) and (2) to get intersection point required:
(1)-(2)
2x-2x + 4y-(-y) -3 -(-4) =0
5y=-1, y=-1/5
Substitute y=1/5 in equation (1)
2x+4(-1/5)-3=0 =>
2x-19/5=0
x=19/10
=> the point on L1 closest to (2,0) is (19/10, -1/5)
Answer:

Step-by-step explanation:
