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3 years ago

"Four times the difference of a number and seven is at least -52."

1 answer:

7 0

Remember ‘difference’ refers to subtraction, so they are looking for the ‘difference’ of a a number, which is unknown, so we can use the variable ‘x.’ X-7

The term ‘at least’ refers to our greater than, less than, equal to signs

Difference of a number and 7 = x-7
Four times = (4) or •4
At least = <
-52 = Answer negative 52
Plug them all in,

x-7(4)<-52

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dlinn [17]

He can only make 2!
Explanation: 7 can only go into 17 twice

Hope this helps!:)

5 0

3 years ago

The base of a solid right pyramid is a regular hexagon with a radius of 2x units and an apothem of units. A solid right pyramid

Xelga [282]

Answer:

$6 x^2*\sqrt{3}$

Step-by-step explanation:

The base of the pyramid we need to study is a hexagon.

Let's look at the attached image of an hexagon to understand how we are going to find the area of this figure.

Notice that an hexagon is the combination of 6 exactly equal equilateral triangles in our case of size "2x" (notice that the "radius" of the hexagon is given as "2x")

Therefore the area of the hexagon is going to be 6 times the area of one of those equilateral triangles.

We know the area of a triangle is the product of its base times its height, divided by 2: $\frac{base*height}{2} = \frac{2x*height}{2}$

We notice that the triangle's height is exactly what is called the "apothem" of the hexagon (depicted in green in our figure) which measures $x\sqrt{3}$ , so replacing this value in the formula above for the area of one of the triangles:

$\frac{2x*height}{2}= \frac{2x*x\sqrt{3} }{2}=x^2\sqrt{3}$

Then we multiply this area times 6 to get the total area of the hexagon (6 of these triangles):

Area of hexagon = $6x^2\sqrt{3}$

which is the last option given in the list.

5 0

3 years ago

Read 2 more answers

Solve 4x^2 - 36x + 32 = 0<br><br>Sorry! It's suppose to be + 32.<br>Please show all work.

mylen [45]

Answer:

x=1, x=8

Step-by-step explanation:

4x2−36x+32=0

Step 1: Factor left side of equation.

4(x−1)(x−8)=0

Step 2: Set factors equal to 0.

x−1=0 or x−8=0

(+1) (+8)

x=1 or x=8

6 0

3 years ago

Classify each pair of angels listed below as adjacent or vertical.

Stolb23 [73]

Answer:

ntersecting lines DA and CE.

To find:

Each pair of adjacent angles and vertical angles.

Solution:

Adjacent angles are in the same straight line.

Pair of adjacent angles:

(1) ∠EBD and ∠DBC

(2) ∠DBC and ∠CBA

(3) ∠CBA and ∠ABE

(4) ∠ABE and ∠EBD

Vertical angles are opposite angles in the same vertex.

Pair of vertical angles:

(1) ∠EBD and ∠CBA

(2) ∠DBC and ∠EBA

5 0

3 years ago

If M is the set of all square numbers less than 80 and N is the set of all non-negative even numbers that are under 30, Write th

Nat2105 [25]

Answer:

Step-by-step explanation:

All square numbers are numbers formed by squaring a single number. If M is the set of all square numbers less than 80, then

M = (4, 9, 16, 25, 49, 64)

Even numbers are numbers that are divisible by 2 without remainder.

If N is the set of all non-negative even numbers that are under 30, then

N = (2, 4, 6, 8 ,10, 12, 14, 16,18,20, 22, 24, 26,28)

It will not include 30 because we want even numbers under 30

8 0

3 years ago