Complete Question
Two different red-light-running signal systems were installed at various intersection locations with the goal of reducing angle-type crashes. Red-Light-Running System A resulted in 60% angle crashes over a sample of 720 total crashes. Red-Light-Running System B resulted in 52% angle crashes over a sample of 680 total crashes. Was there a difference between the proportions of angle crashes between the two red-light-running systems installed? Use an alpha of 0.10.
Answer:
Yes there is a difference between the proportions of angle crashes between the two red-light-running systems installed
Step-by-step explanation:
From the question we are told that
The first sample proportion is 
The second sample proportion is 
The first sample size is 
The second sample size is 
The level of significance is 
The null hypothesis is 
The alternative hypothesis is 
Generally the pooled proportion is mathematically represented as

=> 
=> 
Generally the test statistics is evaluated as
![t = \frac{ ( \r p_1 - \r p_2 ) - 0 }{ \sqrt{ (p_p (1- p_p) * [ \frac{1}{n_1 } + \frac{1}{n_2 } ])} }](https://tex.z-dn.net/?f=t%20%20%3D%20%20%5Cfrac%7B%20%28%20%5Cr%20p_1%20%20-%20%5Cr%20p_2%20%29%20%20-%200%20%7D%7B%20%5Csqrt%7B%20%28p_p%20%20%281-%20p_p%29%20%20%2A%20%20%5B%20%5Cfrac%7B1%7D%7Bn_1%20%7D%20%2B%20%20%5Cfrac%7B1%7D%7Bn_2%20%7D%20%20%5D%29%7D%20%7D)

The p-value obtained from the z-table is
From the question we see that
so the null hypothesis is rejected
Hence we can conclude that there is a difference between the proportions
Answer:
0.0245
Step-by-step explanation:
1. Divide 2.45 by 100 since you are finding it as a percent, which is 100.
Answer:
1/2,-1/2,1/2,-1/2
Step-by-step explanation:
hope helpa
To find a 2-dimensional shape like a cylinder you say V=πr²h
to find a 3-dimensional shape like a sphere you will have V=4πr³÷3
-25 + 2 = -23 and... -25 × 2 = - 50
hope that helps :D