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3 years ago

6

Line segment KI is tangent to crcle J at point K What is the length of the radius, ? O 8 unts O 10 units O 12 units O 16 units 2

4 16

1 answer:

pshichka [43]3 years ago

4 0

08 units i love thes

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What system of inequalities is graphed below?

kirill115 [55]

$y\geq x^2-4-blue\\\\y < x^2+6-red\\\\Answer:\text{I think is D.}\\y\geq x^2-4\\y < x^2+6$

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3 years ago

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The hypotenuse of a right triangle has length 50 cm. One leg has length 20 cm. The nearest tenth, what is the length of the othe

Fantom [35]

Answer:

45.8 cm

Step-by-step explanation:

Let the length of other leg be l

By pythagoras theorem,

$l \: = \sqrt{ {50}^{2} - {20}^{2} } \\ l \: = 45.8cm$

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3 years ago

Does the point (-9,-4) satisfy the equation y = x + 5?

ozzi

Answer:

Yes it satisfies the equation

Step-by-step explanation:

Let, P(x,y) = (-9,-4)

Then, x = -9

y = -4

if we use this value in the equation, we will get L.S = R.S ;(-4 = -9 + 5)

So, the point satisfies the equation

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3 years ago

Please help me???????

Troyanec [42]

Part 1
1. 16-composite
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7 0

3 years ago

1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t

natta225 [31]

The area of the surface given by $\vec r_1(u,v)$ is 1. In terms of a surface integral, we have

$1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

By multiplying each component in $\vec r_1$ by 5, we have

$\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}$

and the same goes for the derivative with respect to $v$ . Then the area of the surface given by $\vec r_2(u,v)$ is

$\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}$

8 0

3 years ago