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Mars2501 [29]
3 years ago
13

Water can flow freely into a gummy bear. Which of the following is a term for movement across a cell membrane that does not requ

ire energy?
active transport


passive transport


idle transport
Biology
2 answers:
Natasha_Volkova [10]3 years ago
8 0
TRANSPORT is the movement through membranes, and Diffusion and osmosis are passive forms of transport; this means that do not need energy to move areas of high concentration to areas of low concentration. so your answer would be passive transport. test are so dumb these days haha<span />
Simora [160]3 years ago
6 0

The right option is; Passive transport

Passive transport is process by which ions and other molecular substances moves across cell membranes or from a region of higher concentration to a region of lower concentration without need of energy input. Passive transport is a simple, natural form of membrane transport that does not need the cell to utilize energy to achieve the movement.


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In liquid media or broth difference between dry and wet will give biomass of the Epulopiscium.

Explanation:

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3 years ago
Explain metabolism as attribute of Living Organism​
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Part C
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Answer:

                     (i) 1 moles of C

                     (ii) 4.5 moles of C

Explanation:

                   The Chemical equation is as follow,

                                             A + 2 B  →  C

This chemical equation can be translated as;

(i) 1 mole of A reacts with 2 moles of B

(ii) 1 mole of A produces 1 mole of C

(iii) 2 moles of B reacts with 1 mole of A

(iv) 2 moles of B produces 1 mole of C

(v) 1 mole of C is produced by 1 mole of A and 2 moles of B

Therefore to find the number of moles of C produced by 2 mole of B we will do following proportional method.

As,

                        2 moles of B produced  =  1 mole of C

So,

                    2 moles of B will produce  =  X moles of C

Solving for X,

                      X =  2 moles × 1 mole / 2 moles

                      X =  1 moles of C

Note:

         In above problem the given moles were the same as that present in balance equation so incase if the moles are different from that of the equation then the method shown above can be used to solve it.

Lets try it for 9 moles of B:

As,

                        2 moles of B produced  =  1 mole of C

So,

                    9 moles of B will produce  =  X moles of C

Solving for X,

                      X =  9 moles × 1 mole / 2 moles

                      X =  4.5 moles of C

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