All categories

3 years ago

What's the least common multiple of 2 and 3

Mathematics

2 answers:

Serga [27]3 years ago

7 0

6 is the least common multiple of 2 and 3

dem82 [27]3 years ago

4 0

Answer:

its 6............................

You might be interested in

Given the following similar triangles,what is the area of triangle B

iren [92.7K]

Answer: 3.2 i think

Step-by-step explanation:

3 0

3 years ago

iogann1982 [59]

Okay thanks for letting me know I love you love love bye

4 0

3 years ago

Decide whether the two expressions are equivalent for each problem below.

Vesnalui [34]

Answer:

Step-by-step explanation:

6 0

2 years ago

A.Sum of integer and its additive inverse is ___________.B.Sum of -22 and -44 is ______________.C.-36 ÷ ( ___)=-9d._________ is

Ede4ka [16]

Answer:

A. 0

B. -66

C. 4

D. 998

E. -12

Step-by-step explanation:

A. By definition, the sum of anything and its additive inverse is zero.

B. If you have trouble with sums, your calculator can help.

-22 + (-44) = -22 -44 = -66

C. -36/x = -9 can be solved by multiplying by x and dividing by -9:

-36 = -9x

-36/-9 = x = 4

Since the product of the divisor and quotient is the dividend, dividing the dividend by either gives the other. Here, your dividend is -36 and your quotient is -9. To find the divisor, you can divide -36 by -9, as we did.

D. The absolute value function changes the sign of negative numbers to positive:

|-998| = 998

E. If you have trouble with sums, your calculator can help.

(−2)−[(−3)−(−7)−(−6)]

= -2 -(-3 +7 +6) = -2 -10 = -12

4 0

3 years ago

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago