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lisov135 [29]
3 years ago
7

What's the least common multiple of 2 and 3

Mathematics
2 answers:
Serga [27]3 years ago
7 0
6 is the least common multiple of 2 and 3
dem82 [27]3 years ago
4 0

Answer:

its 6............................

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Step-by-step explanation:


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Decide whether the two expressions are equivalent for each problem below.
Vesnalui [34]

Answer:

Step-by-step explanation:

6 0
2 years ago
A.Sum of integer and its additive inverse is ___________.B.Sum of -22 and -44 is ______________.C.-36 ÷ ( ___)=-9d._________ is
Ede4ka [16]

Answer:

  A. 0

  B. -66

  C. 4

  D. 998

  E. -12

Step-by-step explanation:

A. By definition, the sum of anything and its additive inverse is zero.

__

B. If you have trouble with sums, your calculator can help.

  -22 + (-44) = -22 -44 = -66

__

C. -36/x = -9 can be solved by multiplying by x and dividing by -9:

  -36 = -9x

  -36/-9 = x = 4

Since the product of the divisor and quotient is the dividend, dividing the dividend by either gives the other. Here, your dividend is -36 and your quotient is -9. To find the divisor, you can divide -36 by -9, as we did.

__

D. The absolute value function changes the sign of negative numbers to positive:

  |-998| = 998

__

E. If you have trouble with sums, your calculator can help.

  (−2)−[(−3)−(−7)−(−6)]

  = -2 -(-3 +7 +6) = -2 -10 = -12

4 0
3 years ago
The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true
Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478

<u>Part B</u>

P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767

<u>Part C</u>

\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971

6 0
2 years ago
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