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3 years ago

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Sin150+sin120÷cos210-cos300

1 answer:

natulia [17]3 years ago

6 0

From sin(180-x) = sin(x)
sin(150) = sin(180-30) = sin(30)
sin(120) = sin(180-60) = sin(60)

from cos(360-x) = cos(x)
cos(300) = cos(360-60) = cos(60)
cos(210) = cos(360-150) = cos(150)

from cos(180-x) = -cos(x)
cos(210) = cos(150) = cos(180-30) = -cos(30)

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Given:

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The value of $(f\circ g)(1)$ .

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$f(x)=x^2-1$

$g(x)=\sqrt{x}$

We need to find the value of $(f\circ g)(1)$ .

$(f\circ g)(1)=f(g(1))$ $[\because (f\circ g)(x)=f(g(x))]$

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