All categories

3 years ago

Sin150+sin120÷cos210-cos300

1 answer:

6 0

From sin(180-x) = sin(x)
sin(150) = sin(180-30) = sin(30)
sin(120) = sin(180-60) = sin(60)

from cos(360-x) = cos(x)
cos(300) = cos(360-60) = cos(60)
cos(210) = cos(360-150) = cos(150)

from cos(180-x) = -cos(x)
cos(210) = cos(150) = cos(180-30) = -cos(30)

You might be interested in

Choose all steps that contain the number 5

stepladder [879]

Answer:

where are the steps....

Step-by-step explanation:

6 0

2 years ago

Which of the graphs below represents the equation 8x - y = -4?

vichka [17]

Well since you dont have the graphs posted i can tell u the y-intercept and the slope and you can figure it out from there.

8x-y=-4
-y=-8x-4
y=8x+4
the y intercept is 4 and the slope is positive 8

4 0

3 years ago

Read 2 more answers

bazaltina [42]

Answer:

c. 0.9 cm, 1.2 cm, 1.8 cm

please mark brainlist

4 0

3 years ago

Read 2 more answers

Increase the number 60 by 30%

Natalija [7]

Answer:

Step-by-step explanation:

10% = 6

⬇️ x3

30% = 18

⬇️ Add onto 60

60+18=78

4 0

2 years ago

Read 2 more answers

Solve the following system by any method -8x-8y=0 -8x+2y=-20

iVinArrow [24]

$\fbox{Solution by using Matrix}$

$\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20$

$\text{Rewrite the linear equations above as a matrix}$

$\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right]$

$\text{Apply to Row2 : Row2 + Row1}$

$\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right]$

$\text{Note: The matrix is now in echelon form.}$ $\text{The steps below are for back substitution.}$

$\text{Apply to Row1 : Row1 + 8 Row2}$

$\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right]$

$\text{Therefore, the solution is}$

$x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}$

7 0

2 years ago