Part A.
You need two equations with the same slope and different y-intercepts.
Their graph is parallel lines. Since the lines do not intersect, there is no solution.
y = 2x + 2
y = 2x - 2
Part B.
We use the first equation as above. For the second equation, we use an equation with different slope. Two lines with different slopes always intersect.
y = 2x + 2
y = -2x - 2
In the second equation, y = -2x - 2. We now substitute -2x - 2 for y in the first equation.
-2x - 2 = 2x + 2
-4x = 4
x = -1
Now substitute -1 for x in the first equation to find y.
y = 2x + 2
y = 2(-1) + 2
y = -2 + 2
y = 0
Solution: x = -1 and y = 0
Centripetal acceleration is given by:
g=v^2/r
where:
v=velocity
r=rate
But
V=200 m/s, g=9.8 m/s^2
plugging the values in the formula we obtain:
9.8=200^2/r
r=200^2/9.8
r=4081.63 m
Answer: $7,605
Step-by-step explanation:
At the end of 1 years, the amount in the account will be:
= Principal * (1 + rate)^ no. of periods
= 6,500 * (1 + 17%)
= $7,605
Item 4 Find the median, first quartile, third quartile, and interquartile range of the data. 132,127,106,140,158,135,129,138 med
Ket [755]
Answer:
133.5, 127.5, 139.5, 12
Step-by-step explanation:
order data:
106, 127, 129, 132, 135, 138, 140, 158
Median:
The middle number: (8+1)/2 = 4.5 between the 4&5 numbers
= (135-132)/2= 1.5
1.5 + 132 = 133.5
lower quartile (1st quartile):
(8+1)/4 = 2.25 between the 2&3 numbers
(129+127)/4=0.5
0.5+127 = 127.5
upper quartile(3rd quartile):
(8+1)/4 x3 = 6.75 between the 6&7 numbers
(140-138)/4 x3 = 1.5
1.5 + 138 =139.5
Interquartile range:
139.5-127.5= 12
hope this helps
