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3 years ago

Which is a genotype?

Chemistry

1 answer:

Pani-rosa [81]3 years ago

8 0

Answer:

Genotypes are related with the collection of genes expressed in the DNA.

Explanation:

Hello,

In genetics, two specific terms define the characteristics of a living thing; a genotype and a phenotype; thus, phenotypes are related with the physical manifestation of genes, for instance, red hair, blue eyes, long arms and others.

On the other hand, genotypes are related with the collection of genes expressed in the DNA, and they could be for equal alleles or for different alleles, in other words, it is the version of DNA the living thing has.

Regards.

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For the reaction

ddd [48]

Answer:

52.2 g

Explanation:

Step 1: Write the balanced equation

3 KOH + H₃PO₄ ⟶ K₃PO₄ + 3 H₂O

Step 2: Calculate the moles corresponding to 89.7 g of KOH

The molar mass of KOH is 56.11 g/mol.

89.7 g × 1 mol/56.11 g = 1.60 mol

Step 3: Calculate the moles of H₃PO₄ needed to react with 1.60 moles of KOH

The molar ratio of KOH to H₃PO₄ is 3:1. The moles of H₃PO₄ needed are 1/3 × 1.60 mol = 0.533 mol.

Step 4: Calculate the mass corresponding to 0.533 moles of H₃PO₄

The molar mass of H₃PO₄ is 97.99 g/mol.

0.533 mol × 97.99 g/mol = 52.2 g

3 0

3 years ago

An adult human lung has a volume of 2.9 liters. If its volume decreases to 1.2 liters and it contains 0.049 mole of air after it

Lera25 [3.4K]

Answer:

In full volume it contain 0.12 moles.

Explanation:

Given data:

Total volume= Vt = 2.9 L

Decreased volume= Vd = 1.2 L

Number of moles of air present in decreased volume= n = 0.049 mol

Number of moles of air in total volume= n = ?

Solution:

Formula:

Vt/ Vd = n (in total volume) /n ( decreased volume)

2.9 L / 1.2 L = X / 0.049 mol

2.42 = X / 0.049 mol

X = 2.42 × 0.049

X = 0.12 mol

6 0

3 years ago

When 3243. grams of iron (III) chloride are reacted with 511.8 grams of hydrosulfuric acid, which is the limiting reactant?

AleksAgata [21]

Answer:

Hydrosulfuric acid will act as limiting reactant.

Explanation:

Given data:

Mass of iron(III) chloride = 3243.0 g

Mass of hydrosulfuric acid = 511.8 g

Limiting reactant = ?

Solution:

Chemical equation:

2FeCl₃ + 3H₂S → Fe₂S₃ + 6HCl

Number of moles of iron(III) chloride:

Number of moles = mass/molar mass

Number of moles = 3243.0 g/ 162.2 g/mol

Number of moles = 20 mol

Number of moles of hydrosulfuric acid:

Number of moles = mass/molar mass

Number of moles = 511.8 g/ 34.1 g/mol

Number of moles = 15 mol

Now we will compare the moles of both reactant with products

FeCl₃ : Fe₂S₃

2 : 1

20 : 1/2 ×20 = 10

FeCl₃ : HCl

2 : 6

20 : 6/2 ×20 = 60

H₂S : Fe₂S₃

3 : 1

15 : 1/3 ×15 = 5

H₂S : HCl

3 : 6

15 : 6/3 ×15 = 30

Hydrosulfuric acid producing less number of moles of product thus, it will act as limiting reactant.

5 0

3 years ago

If one gram of sulphur dioxide contains x molecules what will be the number of molecules in 1g of methane

evablogger [386]

The ratio of molecules in sulphur dioxide and methane will be the same as the ratio of their moles. So, first of all we should find out the number of moles of sulphur dioxide in 1 gram of sulphur dioxide in 1 gram of sulphur dioxide, and the number of moles of methane in 1 gram of methane. This can be done as follows :

(i) The molecular formula of sulphur dioxide is $SO_{2}$

So, $1$ mole of $SO_{2}$ = $Mass$ $of$ $2'O'$

$=32+2*16$

$= 64$ grams

Now, $64g$ of sulphur dioxide $= 1$ mole

So, $1g$ of sulphur dioxide = $\frac{1}{64}$ mole

Thus, we have $\frac{1}{64}$ mole of sulphur dioxide and it contains molecules in it. Now, since equal moles of all the substance contain equal number of molecules, therefore, $\frac{1}{64}$ mole of methane will also contain x molecules of methane.

(ii) Molecular formula of methan is $CH_{4}$