1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
s2008m [1.1K]
3 years ago
10

Mercury is often released into water bodies with industrial effluents, where it is then converted to the compound form methylmer

cury. Methylmercury is easily absorbed by aquatic organisms.
Research suggests that the presence of mercury seriously decreases the reproductive rate of fish-eating birds, like heron, and causes other notable harmful effects. On the other hand, the small fish on which the herons prey are not significantly affected.

Explain why the toxic effects of mercury is significant in herons, but not in the fish they eat.
Chemistry
1 answer:
sergeinik [125]3 years ago
7 0
 This is more to do with Bioaccumulation of mercury, where the mercury is absorbed into the issue of animals, and so animals higher in the food chain consume a lot of tissue matter hence increasing mercury content in their system.
You might be interested in
Carbon in the atmosphere is most often found as which of the following compounds? A. stratospheric ozone B. fossil fuel C. carbo
ad-work [718]
Please help me answer your questions about how I feel you have a good time to carbon dinosaurs in the past and
6 0
3 years ago
Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s
Mamont248 [21]

Answer:

2.15 mg of uranium-238 decays

Explanation:

For decay of radioactive nuclide-

                        N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

where N is amount of radioactive nuclide after t time, N_{0} is initial amount of radioactive nuclide and t_{\frac{1}{2}} is half life of radioactive nuclide

Here N_{0}=4.60 mg, t=4.1\times 10^{9}yr and t_{\frac{1}{2}}=4.5\times 10^{9}yr

So,N=(4.60mg)\times (\frac{1}{2})^{\frac{4.1\times 10^{9}}{4.5\times 10^{9}}}

so, N = 2.446 mg

mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg

3 0
3 years ago
The Brahman cattle have good resistance to high temperature, but its meat is poor and tough to eat. The English shorthorn cattle
N76 [4]

Answer:

d

Explanation:

4 0
3 years ago
Read 2 more answers
A fifth-grade science class puts half of a white tablet in a test tube with 10 milliliters (mL) of water at 21°C (70°F). The tab
hichkok12 [17]

Answer:

change in water tempreture.

Explanation:

5 0
3 years ago
What are the products of a neutralization reaction?
vfiekz [6]
In an acid and base neutralization reaction, the products are salt and water.
3 0
3 years ago
Read 2 more answers
Other questions:
  • What causes water molecules to be attracted to each other?
    10·2 answers
  • What is stp? provide an answer using at least two different units of pressure and complete sentences?
    8·1 answer
  • Why is carbon the basis for the many different kinds of organic molecules? Select all that apply. A. It can connect with several
    5·1 answer
  • What holds combinations of atoms together in molecules? protons and electrons atomic magnetism chemical bonds nuclear forces?
    15·2 answers
  • give a general description of the location of metals , non metals and metalloids on the periodic table
    15·1 answer
  • What is the pH of a solution that has a hydrogen ion concentration of 1.0 * 10 -9 M? Show your calculation.
    5·1 answer
  • Identify and name the functional group present<br> CH4
    8·1 answer
  • List one or two ideas or questions you have about Mars. You can make the questions or ideas complex or simple! Just please put i
    12·2 answers
  • How many grams of Krypton gas will exert a pressure of 5.43 atm in a 5.80-liter container at 25°C?
    10·1 answer
  • Which of the "planetary health measures" shown here have humans already exceeded?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!