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kvasek [131]
3 years ago
15

What are the three conditions that can cause a chemicl reactions, give examples? Help me plz

Chemistry
1 answer:
finlep [7]3 years ago
7 0
Acid. that’s all i know.
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If the atom is assumed to be a sphere, what is the volume in cm3 of a single copper (cu) atom?
kompoz [17]

Atomic radius of copper atom (r)= 128 pm

volume of sphere = 4/3 * pi * r^3 = 4/3 * 3.14 * 128^3

volume = 8780076.373 pm^3

5 0
3 years ago
Help!!!!please i need to get this done before 3pm!today
Lunna [17]
4. 2 miles/ hour
5. 80 hours
6. 408 miles
7. a) 0
b) 500 N [right]
c) 200 N [left]

I don’t know what it meant by resultant force, but i think it’s basically the same as net force.

Hope this helps!!

3 0
3 years ago
What is the concentration of the hydroxide ion? Given that the concentration of the hydronium ion is 2.3 X 10^-7 M
professor190 [17]

Answer:

4.35 * 10^-8 M

Explanation:

Since the concentration of the hydronium ion= 2.3 X 10^-7 M

And we know that;

[H3O^+] [OH^-] = 1 * 10^-14

[H3O^+]  = concentration of the hydronium ion

[OH^-] = concentration of the hydroxide ion

So;

[OH^-] =1 * 10^-14/[ H3O^+]

But [H3O^+] = 2.3 X 10^-7 M

[OH^-] = 1 * 10^-14/2.3 X 10^-7

[OH^-] = 4.35 * 10^-8 M

8 0
3 years ago
Q8.what happened to the mixture?
Natali [406]
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3 0
3 years ago
using the soubility curve what is the solubilityof nh4cl in 10 mL of water at a temperature of 60 degrees Celsius​
lukranit [14]

Answer:

Please, see attached two figures:

  • The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.

  • The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.

  • Answer: <u>5.5g</u>

Explanation:

The red  arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the <em>solubility</em> of <em>NH₄Cl.</em>

From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.

Assuming density 1.0 g/mol for water, 10 mL of water is:

            10mL\times 1.0g/mL=10g

Thus, the solutibily is:

      10gWater\times 55gNH_4Cl/100gWater=5.5gNH_4Cl

5 0
3 years ago
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