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Rina8888 [55]
3 years ago
12

For the reaction

Chemistry
1 answer:
ddd [48]3 years ago
3 0

Answer:

52.2 g

Explanation:

Step 1: Write the balanced equation

3 KOH + H₃PO₄ ⟶ K₃PO₄ + 3 H₂O

Step 2: Calculate the moles corresponding to 89.7 g of KOH

The molar mass of KOH is 56.11 g/mol.

89.7 g × 1 mol/56.11 g = 1.60 mol

Step 3: Calculate the moles of H₃PO₄ needed to react with 1.60 moles of KOH

The molar ratio of KOH to H₃PO₄ is 3:1. The moles of H₃PO₄ needed are 1/3 × 1.60 mol = 0.533 mol.

Step 4: Calculate the mass corresponding to 0.533 moles of H₃PO₄

The molar mass of H₃PO₄ is 97.99 g/mol.

0.533 mol × 97.99 g/mol = 52.2 g

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Traveling at the speed of light - how long would it take, in years, to reach the top of the pile of balls? Show all calculations
marusya05 [52]

The time taken for the object to reach to top of pile is 0.012 year.

<h3>Time of motion </h3>

The time taken for the object to reach to top of pile is calculated as follows;

time of motion = distance traveled/speed

time of motion = (1.1 x 10¹⁴ x 10³ m)/(3 x 10⁸ m/s)

where;

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7 0
2 years ago
N2(g) + 3H2(g) → 2NH3(g) How many grams of N2 are required to produce 240.0g NH3?
just olya [345]

Answer:

\large \boxed{\text{197.4 g}}

Explanation:

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:     28.01               17.03

            N₂ + 3H₂ ⟶ 2NH₃

m/g:                          240.0

(a) Moles of NH₃

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(b) Moles of N₂

\text{Moles of N$_{2}$} = \text{14.09 mol NH}_{3} \times \dfrac{\text{1 mol N$_{2}$}}{\text{2 mol NH}_{3}} = \text{7.046 mol N$_{2}$}

(c) Mass of N₂

\text{Mass of N$_{2}$} =\text{7.046 mol N$_{2}$} \times \dfrac{\text{28.01 g N$_{2}$}}{\text{1 mol N$_{2}$}} = \textbf{197.4 g N$_{2}$}\\\\\text{The reaction requires $\large \boxed{\textbf{197.4 g}}$ of N$_{2}$}

7 0
3 years ago
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What is the one thing that happens in every chemical change?
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Answer:

Explanation:

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Highlight the claim.
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