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andrew11 [14]
3 years ago
11

Compare the process of solving |x - 1 + 1 < 15 to that of solving 1x – 1| + 1 > 15.

Mathematics
1 answer:
Luden [163]3 years ago
8 0

Answer:

x-1+1<15; this gonna be x<15 and 1x-1+1>15 this is gonna be the same

Step-by-step explanation:

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2 years ago
Please help i dont get this at all
Tom [10]

Answer:

\frac{20y^{2} a^{2} }{41bx^{3} }

Step-by-step explanation:

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\frac{5x^{2}y^{3}  }{2a^{5}b^{4}  } *  \frac{8a^{7}b^{3}  }{41x^{5}y  }

2) Cross cancel factors:

\frac{5y^{2}   }{2b  } *  \frac{8a^{2}  }{41x^{3}  }

3) Multiply:

\frac{40y^{2} a^{2} }{82bx^{3} }

4) Simplify:

\frac{20y^{2} a^{2} }{41bx^{3} }

4 0
3 years ago
Read 2 more answers
If x - y =5, x + y =1, then x^2 - y^2= ??<br><br>+explanation please and thanks​
Sveta_85 [38]
<h3>Answer:  5</h3>

=================================

Explanation:

Apply the difference of squares rule

x^2 - y^2 = (x-y)(x+y)

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x^2 - y^2 = 5

----------

Alternatively, you can solve the system

\begin{cases}x-y=5\\x+y = 1\end{cases}

for x and y to get (x,y) = (3,-2).

Then compute x^2-y^2 = 3^2-(-2)^2 = 9-4 = 5

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2 years ago
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fredd [130]

Answer:

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Step-by-step explanation:

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3 years ago
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6 0
3 years ago
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