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zysi [14]
4 years ago
6

What is the radius of a circle with an area of 32.1 square feet

Mathematics
1 answer:
erik [133]4 years ago
6 0
3.2 is the answer.
 
If you want to learn the steps to the process
just copy and paste this "how to find the radius of a circle with an area."
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Graph ​ y−5=−2/3(x+9) ​ using the point and slope given in the equation. Use the line tool and select two points on the line. Pl
grigory [225]
<span>y−5=−2/3(x+9)
</span><span>y−5=−2/3x - 6
</span>y=−2/3x +1

y=−2/3x +1
This graph would look like relatively steep negative graph, with a y-intercept of 1.

5 0
3 years ago
Read 2 more answers
What is 7 ⅖ decreased by 4 4/5 ?​
kobusy [5.1K]

Answer:

2 3/5

Step-by-step explanation:

7 2/5 decreased by 4 4/5, Is the same as 7 2/5 - 4 4/5, which equals to 2 3/5.

6 0
3 years ago
Multiply the binomials and simplify so that they are in standard form. Show all your work.
tatuchka [14]

Answer: The answer is = 2x^2 -11x-40

Step-by-step explanation: a= 2x, b=5, c= x, d =8

= 2xx + 2x (-8) + 5x +5(-8)

+ (-a)=-a

then simplify =2xx-2 -8x+5x.8

2xx=2x^2

2.8x=16x

5.8=40

=2x - 16x + 5x- 40

8 0
4 years ago
Read 2 more answers
6u + 3u =18<br> simplify your answer as much as possible
tino4ka555 [31]
6u + 3u = 18
9u = 18
u = 18/9
u = 2
4 0
4 years ago
Model With Mathematics A photographer is
Damm [24]

Answer:

a. The possible dimensions of the total area are;

The width of the total area is (2·x + 8) inches

The length of the total area is (2·x + 10) inches

b. The dimensions of the photos are as follows;

The length of the photos are 10 inches

The width of the photos are 8 inches

Step-by-step explanation:

a. Given that the area, A = 4·x² + 36·x + 80

We get;

A = 4 × (x² + 9·x + 20) = 4 × (x + 4) × (x + 5) = (2·x + 8)·(2·x + 10)

Therefore, the possible dimensions of the total area (photo + mat) are;

The width of the total area (photo + mat) = (2·x + 8) in.

The length of the total area (photo + mat) = (2·x + 10) in.

b. The dimensions of the photos alone are shorter than the dimensions of the photo and mat combined by 2·x each

Therefore, we have the dimensions of the photos are as follows;

The length of the photo = (2·x + 10) in. - 2·x in. = 10 in.

The width of the photos = (2·x + 8) in. - 2·x in. = 8 in.

3 0
3 years ago
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