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2 years ago

The dot plots compare the number of raffle tickets sold by boys and girls during a school fundraiser which plot has an outlier

Mathematics

1 answer:

Eva8 [605]2 years ago

8 0

Answer:

boys

Step-by-step explanation:

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Read each problem. Write your answer.

k0ka [10]

Answer:

p = -8.4

Step-by-step explanation:

$6(p + 0.4) = 5(p - 1.2) \\ distribute \\ 6p + 2.4 = 5p - 6 \\ 6p - 5p = - 6 - 2.4 \\ p = - 8.4$

6 0

2 years ago

Example and answer,will give brain

Yuri [45]

Answer:

b) -2/5

Step-by-step explanation:

b is -2/5 because its negative and goes down at a rate of 0.4 or 2/5

a , ummmm IDK that, sorry

Brainliest, crown to me

5 0

3 years ago

Lindsay enjoys looking at the different coins people have thrown into the fountain at the mall. Which statement best explains ho

Nina [5.8K]

Answer: Electrons in water act in a similar way to visible light so they don't absorb or reflect most of the light. Instead they allow it to pass through relatively unimpeded, absorbing wavelengths like infrared and reflecting invisible UV

7 0

2 years ago

Y=-8x-4 for what value of x is y equal too -16

boyakko [2]

Answer: X=1.5

Step-by-step explanation:

The equation when y is -16

-16=-8x-4

-12=-8x

12/8 is 1.5

8 0

2 years ago

The town of Hayward (CA) has about 50,000 registered voters. A political research firm takes a simple random sample of 500 of th

timama [110]

Answer: (0.076, 0.140)

Step-by-step explanation:

Confidence interval for population proportion (p) is given by :-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = sample proportion.

n= sample size.

$\alpha$ = significance level .

$z_{\alpha/2}$ = critical z-value (Two tailed)

As per given , we have

sample size : n= 500

The number of Independents.: x= 54

Sample proportion of Independents $\hat{p}=\dfrac{x}{n}=\dfrac{54}{500}=0.108$

Significance level 98% confidence level : $\alpha=1-0.98=0.02$

By using z-table , Critical value : $z_{\alpha/2}=z_{0.01}=2.33$

The 98% confidence interval for the true percentage of Independents among Haywards 50,000 registered voters will be :-

$0.108\pm (2.33)\sqrt{\dfrac{0.108(1-0.108)}{500}}\\\\=0.108\pm2.33\times0.013880634\\\\=0.108\pm0.03234187722\\\\\approx0.108\pm0.032=(0.108-0.032,\ 0.108+0.032)=(0.076,\ 0.140)$

Hence, the 98% confidence interval for the true percentage of Independents among Haywards 50,000 registered voters.= (0.076, 0.140)

8 0

2 years ago