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Aleks04 [339]
3 years ago
13

Help guys!!! i have deadline!!!!

Mathematics
1 answer:
svet-max [94.6K]3 years ago
8 0
Answer: 355.49

Step by Step:
82.14+9.77+31.35+41.25=164.51
520-164.51=355.49
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Answer: a) \frac{x^{2} }{2352.25 } + \frac{y^{2} }{529} = 1

b) The distance of two foci is 85.4 feet

c) Area = 3502.67 square feet

Step-by-step explanation: a) An ellipse has the equation in the form of:

\frac{x^{2} }{a^{2} }+\frac{y^{2} }{b^{2} } = 1, where a is the horizontal axis and b is the vertical axis.

For the Statuary Hall, a = \frac{97}{2} = 48.5 and b = \frac{46}{2} = 23, so the equation will be

\frac{x^{2} }{2352.25 } + \frac{y^{2} }{529} = 1.

b) To determine the distance of the foci, we have to calculate 2c, where c is the distance between one focus and the center of the ellipse. To find c, as a, b and c create a triangle with a as hypotenuse:

a^{2} = b^{2} + c^{2}

c^{2} = a^{2} - b^{2}

c = \sqrt{48.5^{2} - 23^{2} }

c = 42.7

The distance is 2c, so 2·42.7 = 85.4 feet.

The two foci are 85.4 feet apart.

c)The area of an ellipse is given by:

A = a.b.π

A = 48.5 · 23 · 3.14

A = 3502.67 ft²

The area of the floor room is 3502.67ft².

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Answer:

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