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3 years ago

8

“If 5 is decreased from double Joe’s weight, the result is 230. What is Joe’s weight?” Which of the following translations is co

rrect?

1 answer:

gavmur [86]3 years ago

6 0

5+230 then 235 divided by 2 equals your answer

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Suppose that a merchant buys a patio set from the wholesaler for $260

Alina [70]

Answer:

well what is the question here?

Step-by-step explanation:

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3 years ago

Alexeev081 [22]

Answer:

1. 9

2. 10

Step-by-step explanation:

idk if those first 2 are right

6 0

2 years ago

The length of a rectangle is 3 1/6 cm longer than the width. The perimeter of the rectangle is 15 1/3 cm. What are the width and

Delicious77 [7]

The width of rectangle is $2\frac{1}{4}\ cm$ and length is $5\frac{5}{12}\ cm$

Step-by-step explanation:

Let,

Width of rectangle = w

Length of rectangle = w+ $3\frac{1}{6}=w+\frac{19}{6}$

Perimeter of rectangle = $15\frac{1}{3}=\frac{46}{3}\ cm$

Perimeter of rectangle = 2(Length + Width)

$2(w+\frac{19}{6}+w)=\frac{46}{3}\\2(2w+\frac{19}{6})=\frac{46}{3}\\4w+\frac{19}{3}=\frac{46}{3}$

Subtracting $\frac{19}{3}$ from both sides

$4w+\frac{19}{3}-\frac{19}{3}=\frac{46}{3}-\frac{19}{3}\\4w=\frac{46-19}{3}\\4w=\frac{27}{3}\\4w=9$

Dividing both sides by 4

$\frac{4w}{4}=\frac{9}{4}\\w=\frac{9}{4}$

Therefore,

Width of rectangle = w = $\frac{9}{4}=2\frac{1}{4}$ cm

Length of rectangle = $w+\frac{19}{6}=\frac{9}{4}+\frac{19}{6}=\frac{27+38}{12}=\frac{65}{12}=5\frac{5}{12}\ cm$

The width of rectangle is $2\frac{1}{4}\ cm$ and length is $5\frac{5}{12}\ cm$

Keywords: perimeter, addition

Learn more about addition at:

#LearnwithBrainly

7 0

3 years ago

Write and solve inequality ;10 more than 6 times a number is greater than 46

meriva

Is 16x47 what you're asking for? The answer to 16x47 is 752 if that's what you needed.

5 0

3 years ago

Factorize the following algebraic expression:

Hoochie [10]

X^2+16-38=0
find what 2 numbers multiply to get -38 and add to get 16
find factors of 38
2 times 19
there is no way to use common factor so use quadratic formula which is
x= $\frac{ -b+\sqrt{b^2-4ac} }{2a}$ or x= $\frac{ -b-\sqrt{b^2-4ac} }{2a}$

ax^2+bx+c=0 subsitte
a=1
b=16
c=-38
subsitute
$\frac{ -16+\sqrt{16^2-4(1)(-38)} }{2(1)}$ = $\frac{ -16+\sqrt{256+152} }{2}$ = $\frac{ -16+\sqrt{408} }{2}$ = $\frac{ -16+2\sqrt{102} }{2}$ = $-8+\sqrt{102}$
so the answers for x are $-8+\sqrt{102}$ and $-8-\sqrt{102}$ which are aprox -2.099504938362 and +18.099504938362
so it would be
(x-[-8+√102])(x+[8+√102])=0

6 0

2 years ago