Find the average of $.85, $1.35, $7, $1.95, and $2.05
1 answer:
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Answer:
Correct option A: 0.6874
Step-by-step explanation:
Hello!
To calculate the area within the interval [-1.23; 0.83], you have to subtract to the probability accumulated till the lower value to the probability accumulated to the higher value, symbolically:
P(Z≤0.83)-P(Z≤-1.23)
You have to use the Z table to look for the corresponding values of probability. The negative value is in the left entry and the positive value is in the right entry. The first column shows the integer and first decimal value, the second decimal value is in the first row, you cross both values and find the value of probability.
P(Z≤0.83)-P(Z≤-1.23)= 0.7967 - 0.1093= 0.6874
I hope it helps!
1. If you knew that DE = 
CB
Then you would know it is a mid-segment.
2. If you knew that CD = DA and BE = EA (point D and point E are midpoints of their respective segments)
Then you would know it is a mid-segment.
2. If you knew that CD = DA and BE = EA (point D and point E are midpoints of their respective segments)
Answer:
The probability will be 0.3085 or 0
Step-by-step explanation:
Given:
True mean=12.5
Sample mean =12.6
Standard deviation=0.2
Samples=100
To Find:
Probability that exceeds 12.6 ounces.
Solution:
Calculate the Z-score for given means and standard deviation.
So
Z-score= (true mean -sample mean)/standard deviation.
Z-score=(12.5 -12.6)/0.2
=-0.1/0.2
=-0.5
Now Using Z-table
P(X≥-0.5)=p(Z≥-0.5)=0.3085
Hence Probability that sample mean weight exceeds will be 0.3085
OR
By using Normal distribution with sampling ,it will be as follows
Z=(X-u)/[Standard deviation/Sqrt(No of samples)]
Z=(12.6-12.5)/(0.2/Sqrt(100)
Z=0.1/0.2/10
Z=5
So P(X≥12.6 )=P(Z≥5)=1
Pr(Z≥5)=1-1=0.
(Refer the attachment )
Hence Probability of getting ounces greater than 12.6 is '0'.
The sampling is of 0.02 size hence graphically it looks likely.
as shown in attachment.
You've got
just sub the number of the term to findd the term
first term is A(1)=-2(5)^(1-1)=-2(5)^0=-2(1)=-2
4th is A(4)=-2(5)^(4-1)=-2(5)^3=-2(125)=-250
8th term is A(8)=-2(5)^(8-1)=-2(5)^7=-2(78125)=-156250
just sub the number of the term to findd the term
first term is A(1)=-2(5)^(1-1)=-2(5)^0=-2(1)=-2
4th is A(4)=-2(5)^(4-1)=-2(5)^3=-2(125)=-250
8th term is A(8)=-2(5)^(8-1)=-2(5)^7=-2(78125)=-156250