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dybincka [34]
4 years ago
7

7x -3(2x + 1) = 5-3x

Mathematics
2 answers:
Damm [24]4 years ago
7 0

Answer:

2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

7x−3(2x+1)=5−3x

7x+(−3)(2x)+(−3)(1)=5+−3x(Distribute)

7x+−6x+−3=5+−3x

(7x+−6x)+(−3)=−3x+5(Combine Like Terms)

x+−3=−3x+5

x−3=−3x+5

Step 2: Add 3x to both sides.

x−3+3x=−3x+5+3x

4x−3=5

Step 3: Add 3 to both sides.

4x−3+3=5+3

4x=8

Step 4: Divide both sides by 4.

4x

4

=

8

4

x=2

Hoped I helped -

Sleepy~

zavuch27 [327]4 years ago
6 0

Answer:x=2

Step-by-step explanation:

Don’t have to write it all out but if you check it with the equation is works.

Both sides with equal -1 is x is 2.

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Suppose a car uses one gallon of gasoline for every 20 miles traveled.
anzhelika [568]

The miles that can be travelled in the car on $30 gasoline is 240 miles (option A).

<h3>How many miles can the car travel?</h3>

The first step is to determine the total gallons in the car. The total gallons in the car can be determined by dividing the total value of the gasoline the car by the cost per gallon. Division is the process of determining the quotient of two or more numbers.

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Verify that -(x+y)=(-x)+(-y) when x=3/4 and y=2/5
frosja888 [35]

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Will give brainliest, thanks, and 5 stars! LOTS OF POINTS! 50 POINTS!
lubasha [3.4K]

Answer in order:

False

True

False

False

False

False

False

True

True

Step-by-step explanation:

All of the solutions to the equation3x^2 - 12 = 0are x = 12 and x = -12

Solve:

Common factor - 3(x^2-4)=0

Divide both sides

x^2-4=0

Use the quadratic formula

x=\sqrt{4,x}=\sqrt{-4

x = 2, x = -2

Thus, This is false..

-------------------------------------------------------------------------------------------------------------

There are two unique solutions to the equations (x-3)^2 = 16

one variable in matrix = one possible value.

Therefore, x = 7, x = -1

Hence this is True

-------------------------------------------------------------------------------------------------------------

The solutions for the equation 2(x-3)^2-18 = 0 are x = 6 and x = 0

2x^3-18x^2+54x-72=0

x=5.080084

Hence this is false

-------------------------------------------------------------------------------------------------------------

The solutions for the equation 2(x-5)^2-8=0 are x = 7 and x = -7

Add both sides by 8

2(x-5)^2-8+8=0+8

2(x-5)^2=8

(x-5)^2=4

x = 7, x = 3

Hence, this is false

-------------------------------------------------------------------------------------------------------------

The solutions for the equation (x + 3)^2-25 = -8 are x = 2 and x = -8

(x+3)^2=17

x=\sqrt{17-3,}=-\sqrt{17}-3

Hence this is false.

-------------------------------------------------------------------------------------------------------------

The solutions for the equation 2(2x-1)^2=18 are x = 5 and x = -4

(2x-1)^2=9

x=2, x = -1

Hence this is false.

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The only solution for equation (2x-1)^2-49=0 is x = 4

(2x-1)^2=49

x = 4, x = -3

Hence, this is false

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The solutions for the equation 3(x+2)^2 - 3 = 0 are x = -3 and x = -1

3(x+2)^2=3

(x+2)^2=1

x = -1, x = -3

Hence, this is true

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The solutions for the equation 5x^2 - 180 = 0 are x = 6 and x  = -6

Add 180 to both sides

5x^2-180+180=0+180

5x^2 = 180

x^2 = 36

x=\sqrt{36},x=-\sqrt{36}

x = 6, x = -6

Hence, this is true.

-------------------------------------------------------------------------------------------------------------

[RevyBreeze]

7 0
3 years ago
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