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3 years ago

Name 5 fractions that are near 4/12 but not equivalent

1 answer:

3 0

5/12 is close to 4/12
9/24 is also close to 4/12
2/3 is also close to 4/12
3/12 is also pretty close to 4/12
7/24 is also quite close to 4/12
Hope this helps :)

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When June sits down today to read she notices she is on page 20 of a 200 page book. She decides to read 4 pages of this book eve

Olegator [25]

The answer is b. 60 || 4x10=40, 40+20=60

5 0

3 years ago

Read 2 more answers

A company needs $5,400,000 in 14 years in order to expand their factory. How much should the company invest each week if the inv

ludmilkaskok [199]

Answer: the company should invest $12191 each week

Step-by-step explanation:

The amount that the company needs is $5,400,000

We would apply the periodic interest rate formula which is expressed as

P = a/[{(1+r)^n]-1}/{r(1+r)^n}]

Where

P represents the weekly payments.

a represents the amount that the company needs

r represents the rate.

n represents number of weekly payments. Therefore

a = 5,400000

There are 52 weeks in a year

r = 0.079/52 = 0.0015

n = 52 × 14 = 728

Therefore,

P = 5400000/[{(1+0.0015)^728]-1}/{0.0015(1+0.0015)^728}]

5400000/[{(1.0015)^728]-1}/{0.0015(1.0015)^728}]

P = 5400000/{2.98 -1}/[0.0015(2.98)]

P = 5400000/(1.98/0.00447)

P = 5400000/442.95

P = $12191

3 0

3 years ago

PLEASE HELP ILL MARK BRAINEST!!!!

earnstyle [38]

Answer:

(-3,8) would NOT fit the table.

6 0

2 years ago

Read 2 more answers

In the given figure find the value of x and y?<br>Show you works - Thank you!

Vaselesa [24]

<u>EXPLANATION</u><u>:</u>

In ∆ ABC , ∠ABC = 40°

∠CAB = x°
& ∠ACD = 50°

∠ACD is an exterior angle formed by extending BC to D

We know that

The exterior angle of a triangle formed by extending one side is equal to the sum of the opposite interior angles.

∠ACD = ∠CAB + ∠ABC

⇛50° = x° + 40°

⇛x° = 50°-40°

and

In ∆ ACD , AC = CD

⇛ ∠CDA = ∠CAD

Since the angles opposite to equal sides are equal.

Let ∠CDA = ∠CAD = A°

We know that

The sum of all angles in a triangle is 180°

In ∆ ACD,

∠CDA +∠CAD + ∠ACD = 180°

A°+A°+50° = 180°

⇛2A°+50° = 180°

⇛2A° = 180°-50°

⇛2A° = 130°

⇛A° = 130°/2

⇛A° = 65°

now,

∠CDA = ∠CAD = 65°

∠BAC + ∠CAD+y = 180°

Since angles in the same line

10°+65°+y = 180°

⇛75°+y =180°

⇛y = 180°-75°

<u>Answer</u><u>:</u> Hence, the value of “x” & “y” will be 10° and 105° respectively.

4 0

2 years ago

Match each function

Elis [28]

Answer:

* The degree of the function is 4 and the leading coefficient is positive

f(x) = (x + 6)(2x - 3)(x - 1)²

* The degree of the function is 5 and the leading coefficient is negative

f(x) = (x - 2)²(-2x - 1)²(-x + 1)

* The degree of the function is 6 and the leading coefficient is negative

f(x) = (-x + 1)³(x + 2)²(x - 3)

* The degree of the function is 5 and the leading coefficient is positive

f(x) = (-2x + 1)²(x - 3)²(x + 1)

Step-by-step explanation:

∵ f(x) = (x + 6)(2x - 3)(x - 1)²

∵ (x)(2x)(x²) = 2x^4

∴ The degree of the function is 4

∴ The leading coefficient is positive ⇒ (2)

∵ f(x) = (x - 2)²(-2x - 1)²(-x + 1)

∵ (x)²(-2x)²(-x) = (x²)(4x²)(-x) = -4x^5 ⇒ (neglect -ve with even power)

∴ The degree of the function is 5

∴ The leading coefficient is negative ⇒ (-4)

∵ f(x) = (-x + 1)³(x + 2)²(x - 3)

∵ (-x)³(x)²(x) = (-x³)(x²)(x) = -x^6

∴ The degree of the function is 6

∴ The leading coefficient is negative ⇒ (-1)

∵ f(x) = (-2x + 1)²(x - 3)²(x + 1)

∵ (-2x)²(x)²(x) = (4x²)(x²)(x) = 4x^5

∴ The degree of the function is 5

∴ The leading coefficient is positive ⇒ (4)

6 0

3 years ago