If $200 is the maximum a coach can spend on new shorts, and needs at least 15 shorts, then you could divide or use an inequality. first take the maximum number (200) and the minimum amount (15s) and use the minimum and maximum signs of knowledge to form an inequality. you should end up with 15s<200.
Continuing from the setup in the question linked above (and using the same symbols/variables), we have




The next part of the question asks to maximize this result - our target function which we'll call

- subject to

.
We can see that

is quadratic in

, so let's complete the square.

Since

are non-negative, it stands to reason that the total product will be maximized if

vanishes because

is a parabola with its vertex (a maximum) at (5, 25). Setting

, it's clear that the maximum of

will then be attained when

are largest, so the largest flux will be attained at

, which gives a flux of 10,800.
Answer:
15,000
Step-by-step explanation:
1912* 8 =15,296
To the nearest thousand = 15,000
It means different digits.
W=50 would count as one of the digits.
Now you have to figure out what “XYZ” is.
Hey there! :)
Answer:
y = 1/4x - 3.
Step-by-step explanation:
Use the slope-formula to find the slope of the line:

Plug in two points from the line. Use the points (-4, -4) and (0, 3):

Simplify:
m = 1/4.
Slope-intercept form is y = mx + b.
Find the 'b' value by finding the y-value at which the graph intersects the y-axis. This is at y = -3. Therefore, the equation is:
y = 1/4x - 3.