Ask question

Ask question

All categories

Sergio039 [100]

3 years ago

12

PLS HELP!!!!! What is the range of Variable B for the cluster?

1 answer:

DanielleElmas [232]3 years ago

7 0

The answer is 2. Range is subtracting the highest number by the lowest number.

You might be interested in

Need help with other math who’s gonna help me brainlest and points

Over [174]

I haven’t done this is a while but I think x=70

7 0

3 years ago

Helppppp1!!\<br><br> (2x+4)=-4(-2x-6)

yulyashka [42]

Answer:

x=-10/3

Step-by-step explanation:

(2x+4)=-4(-2x-6)

distribute -4 to (-2x-6) by multiplying

negative multiplied by a negative is a positive

8x+24=2x+4

subtract 24 from each side

8x=2x-20

subtract 2x from each side 6x=-20

divide both sides by 6

-20/6

simply to -10/3 or -3 1/3 or -3.3

x=-10/3

hope this helps! if you have any questions please ask!

4 0

1 year ago

2.1 repeating as a mixed number?

Schach [20]

Answer:

2 1/10

Step-by-step explanation:

"Convert the decimal number to a fraction by placing the decimal number over a power of ten. Since there is 1 number to the right of the decimal point, place the decimal number over $10^{1}$ 1 (10). Next, add the whole number to the left of the decimal.

$2\frac{1}{10}$ "

quote desmos

6 0

3 years ago

Which of the following are solutions to the equation below?

sladkih [1.3K]

Answer:

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

Step-by-step explanation:

considering the equation

$2x^2\:-\:4x\:-\:3\:=\:x$

solving

$2x^2\:-\:4x\:-\:3\:=\:x$

$2x^2-4x-3-x=x-x$

$2x^2-5x-3=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

solving

$x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5+\sqrt{49}}{2\cdot \:2}$

$x=\frac{5+7}{4}$

$x=3$

also solving

$x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5-\sqrt{49}}{4}$

$x=-\frac{2}{4}$

$x=-\frac{1}{2}$

Therefore,

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

7 0

3 years ago

The number of wins in the American Baseball League, Central Division, for a recent year is given in the table. Find the mean num

Strike441 [17]

Answer:

add sll number so you will get answer

dd

Step-by-step explanation:

3 0

2 years ago