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aivan3 [116]
3 years ago
7

Please help me whith this

Mathematics
1 answer:
Vinvika [58]3 years ago
3 0

Answer:

Could / Would you do me a favour? Sometimes we want to be polite and ask someone if they are willing to help out in the first place. ...

Could I ask / bother / trouble you + infinitive? ...

Could you / Would you + base form of verb + please? ...

Could you + possibly + verb? ...

Would you mind + verb-ing?

Step-by-step explanation:

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valentinak56 [21]
Angle 1 and angle 5 are equal so you can set the equations equal to each other. 60 - 2x = 70 - 4x 
60 + 2x = 70
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8 0
2 years ago
(08.01)Consider the following system of equations:
Anika [276]

Lines y = −2x + 3 and y = 3x – 5 intersect the x-axis.

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2 years ago
Recall the formula for the area of a trapezoid, A=1/2h(a+b) , where h is the height and a and b are the lengths of the parallel
Gekata [30.6K]

Answer:

The area of the trapezoid is 40 square inches

Step-by-step explanation:

Here, we want to find the area of the given trapezoid

Mathematically, we apply the formula for the area

In this case, a will be 10, b will be 6 and h will be 5

Substituting these values, we have that ;

A = 1/2(10 + 6)5

A = 1/2(16)(5)

A = 40 square inches

7 0
2 years ago
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Sunny_sXe [5.5K]
"a" and integer is a whole number not a fraction or a decimal
7 0
3 years ago
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A spring with a spring constant k of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. It is then st
shutvik [7]

Answer:

Equation of movement y(t)

y(t)=sin(10t-\pi/2)

Amplitude: 1 inch

Period: 0.628 seconds

Step-by-step explanation:

If there is no friction, the amplitude will be the length it was streched from the equilibrium. In this case, this value is 1 inch

A=1\,inch

The period depends on the mass and the spring constant.

The formula for the period is:

T=\frac{1}{f} =\frac{2/pi}{\omega} =2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{1}{100}}=2\pi*0.1=0.628\, s

The model y(t) for the movement of the mass-spring system is

y(t)=A\cdot sin(\omega t +\phi)\\\\A=1\\\\\omega=\sqrt{k/m} =\sqrt{100/1}=10\\\\y(0)=Asin(\phi)=-A\\\\ \phi=arcsin(-1)=-1.571=-\pi/2\\\\\\y(t)=sin(10t-\pi/2)

8 0
3 years ago
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