1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zhannawk [14.2K]
2 years ago
13

Mr. Evan is paid $9.20 per hour for the first 40 hours he works in a week he is paid 1.5 times that rate for each hour after tha

t
Last week Mr. Evan worked 42.25 hours he says he earned $3888.70 last week Do you agree Support your answer
Mathematics
1 answer:
faust18 [17]2 years ago
7 0
That is incorrect. The correct answer should be $398.38
First you take 9.2 times 40 and you get $368 which is how much he got paid for the first 40 hours. now he worked 2.25 hours extra so you take 9.2 * 1.5 because he gets 1.5 times more for extra hours. Then you add that to the $368 and you get $398.38
You might be interested in
A house repair costs 5000 for materials and 200 per hour. Write an equation for the cost c as a function of the hours worked, t
Crank
The answer for this would be
C = 5000 + 200t
4 0
3 years ago
Find the unit rate. $9.30 for 3 gallons
bonufazy [111]

Answer: $3.10 per gallon

Step-by-step explanation: 9.30 divided by 3

7 0
2 years ago
Read 2 more answers
Two objects were lifted by a machine. One object had a mass of 2 kilograms and was lifted at a speed of 2m/sec. the other had a
OLga [1]
Sadly, after giving all the necessary data, you forgot to ask the question.
Here are some general considerations that jump out when we play with
that data:

<em>For the first object:</em>
The object's weight is (mass) x (gravity) = 2 x 9.8 = 19.6 newtons
The force needed to lift it at a steady speed is 19.6 newtons.
The potential energy it gains every time it rises 1 meter is 19.6 joules.
If it's rising at 2 meters per second, then it's gaining 39.2 joules of
     potential energy per second.
The machine that's lifting it is providing 39.2 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(2)(4) = 4 joules.

<em>For the second object:</em>
The object's weight is (mass) x (gravity) = 4 x 9.8 = 39.2 newtons
The force needed to lift it at a steady speed is 39.2 newtons.
The potential energy it gains every time it rises 1 meter is 39.2 joules.
If it's rising at 3 meters per second, then it's gaining 117.6 joules of
     potential energy per second.
The machine that's lifting it is providing 117.6 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(4)(9) = 18 joules.

If you go back and find out what the question is, there's a good chance that
you might find the answer here, or something that can lead you to it.

4 0
3 years ago
Use the data set below to determine measurements of central tendency.
notka56 [123]
Mean = 40 median = 37.5 mode = 30
4 0
2 years ago
What is 6,400,000 written in scientific notation?
Arlecino [84]

Answer:

B

Step-by-step explanation:

6.4 × 1000000 is 6,400,000

10⁶ = 1000000

8 0
2 years ago
Read 2 more answers
Other questions:
  • I will give you a Brainly crown if it is right. Will you help me plzzzzzz helplpppppp
    13·2 answers
  • Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6
    7·1 answer
  • I need the answer asap<br><br> -14p+6=-6p-2
    13·2 answers
  • rhonda had a piece of ribbon that was 5 feet 3 inches long she removed a 5-inch piece to us in her art project what is the lengt
    12·2 answers
  • Write a function in any form that would match the graph shown below.
    6·1 answer
  • HELP PLEASE I NEED THIS FOR GRADUATION
    9·1 answer
  • What is the value of x?<br> x =
    7·1 answer
  • -5 = 1 / 3 ( -1 - w )<br> plz help with step by step answer
    11·1 answer
  • Tell whether side lengths (45, 40, 30) form a right triangle.
    9·1 answer
  • The water level in the pond decreased from 46 feet to 20 feet. What is the percent decrease in the water level rounded to the ne
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!