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RSB [31]
3 years ago
10

A pound of rice crackers costs $2.88. Matthew purchased 1/4 pound of crackers. How much did he pay for crackers?

Mathematics
2 answers:
MakcuM [25]3 years ago
8 0

$2.88/4=.72 cents for 1/4 pound of rice crackers.

Rom4ik [11]3 years ago
6 0
He payed 0.72 
First you take 2.88, then you multiply it by 1/4 or a simpler way would be to divide 2.88 by 4. The answer is $0.72
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4. If f(x) = 5X + 8, g(x) = 7X -2 Find (f - g)(x)
Licemer1 [7]

Answer:

-2x+10

Step-by-step explanation:

f(x)=5x+8

g(x)=7x-2

(f-g)(x)= 5x+8-7x+2= -2x+10

4 0
3 years ago
Eric throws a biased coin 10 times. He gets 3 tails. Sue throw the same coin 50 times. She gets 20 tails. Aadi is going to throw
iren2701 [21]

Answer:

(1) The correct option is (A).

(2) The probability that Aadi will get Tails is \frac{2}{5}.

Step-by-step explanation:

It is provided that:

  • Eric throws a biased coin 10 times. He gets 3 tails.
  • Sue throw the same coin 50 times. She gets 20 tails.

The probability of tail in both cases is:

  • P(\text{Tail})=\frac{3}{10}
  • P(\text{Tail})=\frac{20}{50}=\frac{2}{5}

(1)

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

In this case we need to compute the proportion of tails.

Then according to the Central limit theorem, Sue's estimate is best because she throws it <em>n = </em>50 > 30 times.

Thus, the correct option is (A).

(2)

As explained in the first part that Sue's estimate is best for getting a tail, the probability that Aadi will get Tails when he tosses the coin once is:

P(\text{Tail})=\frac{20}{50}=\frac{2}{5}

Thus, the probability that Aadi will get Tails is \frac{2}{5}.

7 0
4 years ago
Read 2 more answers
What is the equation of the line that passes through (-1, 5) and (3, -7)?
enyata [817]

Answer:

3x + y = 2

Step-by-step explanation:

y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}(x - x_1)

y - 5 = \dfrac{-7 - 5}{3 - (-1)}(x - (-1))

y - 5 = \dfrac{-12}{4}(x + 1)

y - 5 = -3(x + 1)

y - 5 = -3x - 3

3x + y = 2

3 0
3 years ago
An algorithm takes 5 seconds for input size 200. How long will it take for input size 1000 if the running time is linear (assume
tankabanditka [31]

The running time for an input size of 1000 will be 25 seconds.

To calculate the runtime of the Algorithm we need to know what an Algorithm is and how its runtime works.

<h3>What is the runtime of an Algorithm?</h3>

A finite sequence of rigorous instructions, used to solve a critical problem of a specific class or for computational purposes is called an Algorithm. The time taken to complete the said task is called the runtime of an Algorithm.

Let us now solve the question about linear running time of an algorithm.

Input size(N_{1})=200

Time taken(T_1)=5 seconds

Final input size(N_2)=1000

Let the final time taken be T.

Now we know that: \frac{N_1}{T_1}=\frac{N_2}{T_2}

Substituting the values we get T_2=25 seconds .

Therefore the linear running time for an input size of 1000 is 25 seconds.

To know more about Algorithm:

brainly.com/question/17780739

#SPJ4

8 0
2 years ago
Bill and john competed in the shot put event in their school's track meet bill threw the shot 21 feet and 6 inches while john th
Vera_Pavlovna [14]
4 feet 2 inches, 21-17=4 6-4=2
6 0
4 years ago
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