Answer:
127
Step-by-step explanation:
We started at 7
We keep going up 3
multiply
Now add 
at the 40th term
When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)
Thus there are 11 total possible outcomes.
Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)
This means there are 7 outcomes with sum greater than or equal to 9.
Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11
So, option A gives the correct answer
There were 29 days in February 1984.
Descriptions 1, 2, 3, and 5 are accurate, though 5 is ambiguous.
_____
Description 4 goes with (7x)² = 49x², not 7x².
Description 6 goes with 5·8 + x² + (2x + 8) = x² +2x +48, not 40x² +100x +40.
The description for 5 is accurate, but could also be applied to y² + 3(y - 4), which is why it can be considered to be ambiguous. There are a number of ways to resolve the ambiguity, but they were not used here.
