Esay all u do is 180-90=90 becuase right angle mean 90 then do that 90-55 becuase it says one of the angles were 55 so ur answer is C 35
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A) (1,3)
1st number is x
2nd number is y
count to the right 1
up 3
(1,3)
Answer:
It's A and the answer is 4^x
Step-by-step explanation:
Answer:
option no D
Step-by-step explanation:
AS it given that it is a random generator
so it will generate random integers between 1 and 3
so
possible sample space = {1,2,3}
Total no of out comes = 3
Estimated probability that 3 will occur will be obtained by dividing total no of outcomes with total no of possible events to occur
as the occurrence of event is only 1
so
Estimated probability = 1 /3 = 0.33333
Now
The experiment is performed
total outcomes = 14
Total no of like able events that 3 occurred = 4
Actual probability = 4 / 14
= 0.2857
Difference between actual and estimated probability is = 0.3333-0.2857
=0.0421
≅0.04
which is option D
Answer:
It is very unusual as the probability to get a sample average of 75 or more customers if the manager had not offered the discount is 0.006
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 50
Standard Deviation, σ = 10
We are given that the distribution of number of customers is a bell shaped distribution that is a normal distribution.
In an attempt to increase the number of weekday customers, the manager offers a $10 membership discount on 5 consecutive weekdays and the sample mean of customers during this weekday period jumps to 75.
Formula:
a) P(sample average of 75 or more customers if the manager had not offered the discount)
P(x > 75)
Calculation the value from standard normal z table, we have,

It is very unusual as the probability to get a sample average of 75 or more customers if the manager had not offered the discount is 0.006
b) Yes, the managers discount strategy worked as it increased the average number of customers from 50 customers to 75 customers.