Answer:
Step-by-step explanation:
Here you go mate
Step 1
3x(1.05) Equation/Question
Step 2
3x(1.05) Simplify
3x(1.05)
Step 3
3x(1.05) Multiply them
Answer
3.15x
Hope this helps
122.0769 hopefully I helped you out
Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
Converting everything to decimals:
0.25 inch, 0.5 inch, 0.4 inch
Ordering:
0.25, 0.4, 0.5
Converting the appropriate numbers back to fractions:
1/4,10/25,0.5.
