The answer to your question is
1/4 kilometer = 0.25 kilometers = 250 meters
You answer is 250 meters
Rotation of triangle JKL by 180 degrees will result in a triangle with corresponding vertices of (2, 4), (3, 2) and (-1, 2).
Then translating the resulting triangle 2 units up will result in a triangle with corresponding vertices (4, -2), (2, -3) and (2, 1) which is the same triangle as the given triangle MNP.
Therefore, the statement that best explains whether △JKL is congruent to △MNP is △JKL is congruent to △MNP because △JKL can be mapped to △MNP by a
rotation of 180° about the origin followed by a translation 2 units up.
There are four terms in that expression.
Answer:
.76 x 10 or 7.6 x 10^0
Step-by-step explanation:
divide coefficients and subtract exponents
5.4 / 7.1 = .76
10^-7 / 10^-8 = 10
Answer:
Part A:
m∠VHT = 152°
Part B:
m∠QTS = 152°
Part C:
m∠ZHQ = 28°.
Step-by-step explanation:
Part A:
The given parameters are;
m∠HXU = 113°
Segment BQ and segment UD intersect at m∠XAT = 95°
We have that m∠HXU + m∠HXS = 180° (Angles on a straight line)
Therefore;
m∠HXU = 180° - m∠HXS = 180° - 113° = 67°
m∠HXU = 67°
m∠XAT + m∠XAH = 180° (Angles on a straight line)
m∠XAH = 180° - m∠XAT = 180° - 95° = 85°
m∠XAH = 85°
In triangle XAH, we have;
m∠XAH + m∠HXU + m∠XHA = 180° (Angle sum property of a triangle)
∴ m∠XHA = 180° - (m∠XAH + m∠HXU) = 180° - (85° + 67°) = 28°
m∠XHA = 28°
m∠VHT + m∠XHA = 180° (Angles on a straight line)
m∠VHT = 180° - m∠XHA = 180° - 28° = 152°
m∠VHT = 152°
Part B:
m∠QTS ≅ m∠VHT (Corresponding angles are congruent)
∴ m∠QTS = 152° (Substitution property)
Part C:
m∠ZHQ ≅ m∠XHA (Reflexive property)
∴ m∠ZHQ = 28°.