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suter [353]
4 years ago
10

What is the GCF for 98 and 100

Mathematics
2 answers:
vovikov84 [41]4 years ago
5 0
2 is your answer have a nice day

34kurt4 years ago
3 0
The gcf would be 2..
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Lydia graphed ΔXYZ at the coordinates X (0, −4), Y (2, −3), and Z (2, −6). She thinks ΔXYZ is a right triangle. Is Lydia's asser
katrin [286]

Answer:

Option (4)

Step-by-step explanation:

Vertices of the triangle are X(0, -4), Y(2, -3) and Z(2, -6).

Slope of XY (m_{1}) = \frac{y-y'}{x-x'}

                            = \frac{-3+4}{2-0}

                     (m_{1}) = \frac{1}{2}

Similarly, slope of XZ (m_{2}) = \frac{-6+4}{2-0}          

                                   (m_{2}) = (-1)

m_{1}\times m_{2}=-\frac{1}{2}

Which should be (-1) if XY and XZ are perpendicular to each other.

Now we can say that XY and XZ are not perpendicular.

Therefore, Lydia's assertion that ΔXYZ is a right triangle is not correct.

Option (4) will be the answer.

5 0
3 years ago
Find the maximum value of y = -2(x - 4)2 - 6. A) -6 B) -4 C) -2 D) 4
otez555 [7]

Y=-2(x-4)^2-6

The -6 makes it shift from origin(0,0) to (0,-6)

Then the -4 inside with x, makes it shift to the right by for, so the center would be now instead of (0,0), (4,-6).

As it has a negative A factor, it is a parabola open downwards, so the center is the maximum value.

Answer: (4,-6)

Hope you get it!

6 0
4 years ago
Use​ l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove
steposvetlana [31]

Answer:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}

Step-by-step explanation:

The limit is:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}

by replacing, and applying repeatedly you obtain:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}

hence, the limit of the function is -1/14

8 0
3 years ago
20:4 in simplest form
kenny6666 [7]
ANSWER: 20:4 in simplest form is 5:1
7 0
2 years ago
Read 2 more answers
Gina wrote the following paragraph to prove that the segment joining the midpoints of two sides of a triangle is parallel to the
Georgia [21]

Answer: The answers are

(i) The slope of segments DE and AC is not 0.

(ii) The coordinates of D and E were found using the Midpoint Formula.

Step-by-step explanation:  We can easily see in the proof  that the co-ordinates of D and E were found using the mid-point formula, not distance between two points formula. So, this is the first flaw in the Gina's proof.

Also, we see that the slope of line DE and AC, both are same, not equal to 0 but is equal to

\dfrac{y_2}{x_2},

which is 0 only if y_2=0.

So, this is the second mistake.

Thus, the statements that corrects the flaw in Gina's proof are

(i) The slope of segments DE and AC is not 0.

(ii) The coordinates of D and E were found using the Midpoint Formula.

3 0
3 years ago
Read 2 more answers
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