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3 years ago

7

Triangle MNO is similar to triangle MꞌNꞌOꞌ. Segment MN is 2 units and segment MꞌNꞌ is 8 units. Which scale factor was used to di

late triangle MNO to form triangle MꞌNꞌOꞌ?

2 answers:

Simora [160]3 years ago

7 0

My answer is the same as the one above.

Over [174]3 years ago

3 0

In getting the scale factor, use the formula:
Scale factor = big / small
Scale factor = 8 / 2
Scale factor = 4 units

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PLEASE PLEASE PLEASEE PLEASEEEEESE HELPME!?!?!? IM SO BAD AT MATH PLEASE HELP!!!

Fiesta28 [93]

For this case we have the following function:
$f (x) = 0.01 * (2) ^ x
$
By definition, the average rate of change is given by:
$AVR = \frac{f(x2) - f(x1)}{x2 - x1}$
We evaluate the function for the given values:
For x = 7:
$f (7) = 0.01 * (2) ^ 7

f (7) = 1.28$
For x = 14:
$f (14) = 0.01 * (2) ^ {14} f (14) = 163.84$
Then, replacing values we have:
$AVR = \frac{163.84 - 1.28}{14 - 7}$
$AVR = 23.22$
Answer:
the average rate of change from x = 7 to x = 14 is:
a. 23.22

7 0

4 years ago

The value of y varies directly as x and y is 9 when x is -3 what constant of variation k?

Lady bird [3.3K]

Y/x=k

when y=9, then x= -3
9/-3=-3
⇒ k= -3

7 0

3 years ago

a game consists of randomly choosing a bag (labelled 1, 2 or 3) out of a choice of 100, and then again randomly, picking a ball

Anton [14]

Answer:

hello your question has some missing information attached below is the missing information

answer : 112 black balls

Step-by-step explanation:

Given data:

Each bag contains ; 10 balls

Total number of ball = 100 balls

<u>first: calculate the number of Black balls to be picked from the three bags</u>

From bag 1 = 0.4 * 0.35 * 10 = 1.4 balls

From bag 2 = 0.8 * 0.45 * 10 = 3.6 balls

From bag 3 = 0.3 * 0.2 * 10 = 0.6 ball

Total black balls picked = 5.6

∴ percentage of black balls picked given that each bag contains 10

5.6 / 10 * Total balls available = 56 balls = 56% of 100 balls

Hence If the player plays this game 200 times the number of black balls he will pick = 56% * 200 = 112 balls

4 0

3 years ago

Mr. Blue drove from Allston to Brockton, a distance of 105 miles. On his way back, he increased his speed by 10 mph. If the jour

andrew-mc [135]

Answer:

His original speed was 60 mph.

Step-by-step explanation:

The average speed formula is shown below:

speed = distance / time

For the first leg of the trip Mr. Blue drove at a speed of "x" mph, for a distance of 105 miles, therefore the time that took to complete the trip is:

time 1 = distance / speed

time 1 = 105 / x h

On the second leg of the trip Mr. Blue drove faster at a speed of "x + 10" mph, so the time it took him to complete the trip was 15 minutes less, therfore:

time 2 = time1 - (15/60) = (105/x) - 0.25 = (105 - 0.25*x)/x h

Applyint the time and speed from the second leg to the average speed formula we have:

x + 10 = {105/[(105 - 0.25*x)/x]}

x + 10 = 105*x/(105 - 0.25*x)

(x + 10)*(105 - 0.25*x) = 105*x

105*x + 1050 -0.25*x² - 2.5*x = 105*x

-0.25*x² -2.5*x + 1050 = 0 /(-0.25)

x² + 10*x - 4200 = 0

x1 = [-(10) + sqrt((10)² - 4*(1)*(-4200))]/2 = 60

x2 = [-(10) - sqrt((10)² - 4*(1)*(-4200))]/2 = -70

Since his speed couldn't be negative the only possible value was 60 mph.

5 0

3 years ago

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On a manufacturer's assembly line, 3% of its merchandise comes off defective. If the company has 354 defective items, how many t

Rainbow [258]

3% of x = 354 <span>3%∗<span>1<span>100%</span></span>∗x=354</span><span><span><span>3x</span>100</span>=354</span>Can you solve that for x<span>?</span>

8 0

3 years ago

Read 2 more answers