Answer:
D=-4<0, the equation has no real solutions, it has two imaginary solutions.
Step-by-step explanation:
The quadratic equation
has coefficients
a=1,
b=4,
c=5.
The discriminant D is the expression

Hence,

Since the discriminant is negative, the equation has no real solutions, it has two imaginary solutions.
multiply both sides by the reciprical of 5/3 so:
3/5(5/3)w=-10(3/5)
w=-30/5= -6
<u>27 = 6x + 4y </u>= 1 7/20 = 3 4/5<u>
</u>20 = 2x + 5y<u>
</u>