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3 years ago

1 7 1 What is the solution to the equation à x-5-6+3x? X=-5 X=-4 OX= 4 X= 5

Mathematics

1 answer:

Over [174]3 years ago

4 0

Answer:

there 5-5-6+35........

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PLEASE HELP WILL MARK BRAINLIEST NO FAKE ANSWERS OR WILL BE REPORTED

GarryVolchara [31]

Answer:

height is 15

Y = L = Length

therefore 15y = (-x^2) +(300/20)

Step-by-step explanation:

15 = -x^2 +(300/20)

is the same as;

15 = (300/20) - (x^2)

we just add y to 15 and that can represent a division for x

y = L

Where area cm^2 can be shown as 300 as 15 x 20 = 300

when we divide by length we get the height as asked in the question.

7 0

2 years ago

PLEASE HELP ME !!! SOS

kramer

Answer:6x - 2y = 22

Step-by-step explanation:

Just multiplying equation by 2

Can do it with any number

8 0

2 years ago

The equation of a line is given below. 6x -4y = 24. Find the x-intercept and the Y-intercept then use them to graph the line

ipn [44]

Answer:

x intercept is 4 and the y intercept is -6

Step-by-step explanation:

x-int:

6x=24

x=4

y-int:

-4y=24

y=-6

5 0

3 years ago

Can someone simplify this for me and the answer I don’t know help quickly!!!

Vinil7 [7]

Answer:

9/10

Step-by-step explanation:

8 0

1 year ago

There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is

shusha [124]

Answer:

The probability that he picked 2 purpled socks is <u>0.33</u>.

Step-by-step explanation:

Given:

Number of purple socks, $n(P) = 6$

Number of orange socks, $n(O) = 4$

Two socks are picked without replacement.

Now, total number of socks, $n(T)=N(P)+n(O)=6+4=10$

Probability of picking the first cap as purple cap is given as:

$P(P1)=\frac{n(P)}{n(T)}\\\\P(P1)=\frac{6}{10}=\frac{3}{5}$

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

$P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}$

Now, probability that both the picked caps are purple is given by their probability product. This gives,

$P(P1\ and\ P2)=P(P1)\times P(P2)\\\\P(P1\ and\ P2)=\frac{3}{5}\times\frac{5}{9}\\\\P(P1\ and\ P2)=\frac{3}{9}=\frac{1}{3}=0.33$

Therefore, the probability that he picked 2 purpled socks is 0.33

4 0

2 years ago