Question

How can you use a point on the graph of f –1(x) = 9x to determine a point on the graph of f(x) = log9x?

Answer 1

Answer:

Switch the x- and y-coordinates

Step-by-step explanation:

Answer A on Edge-nuity.

Answer 2

Whenever you can invert a function, you have that the graphs of $f(x)$ and its inverse $f^{-1}(x)$ are reflected with respect to the line $y=x$

So, given any point on the graph of $f^{-1}(x)$, you can simply swap its coordinates to get the correspondent point on the original function $f(x)$

As an example, all exponential functions pass through the point $(0,1)$, while all the logarithmic functions pass through the point $(1,0)$