What number does y stand for in this equation?
2 answers:
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The answer is not defined.
Explanation:
The given matrix is
The matrix has dimensions
This means that the matrix has 2 rows and 2 columns.
Also, the matrix has dimensions
This means that the matrix has 2 rows and 1 column.
Since, the matrices can be added only if they have the same dimensions.
In other words, to add the matrices, the two matrices must have the same number of rows and same number of columns.
Since, the dimensions of the two matrices are not equal, the addition of these two matrices is not possible.
Hence, the addition of these two matrices is not defined.
<h3>Answer:</h3>
A. y = -1/3x + 2 . . . . . . . . assuming a typo in your problem statement
<h3>Explanation:</h3>The point (0, 2) is the y-intercept. This tells you the equation will be something of the form ...
... y = mx + 2 . . . . . . matching only answer choices A and C
_____
Knowing this, you can either substitute the values x=3, y=1 into these two equations to see which one works (it is not C), or you can look at the two points and determine the value of the slope.
The slope is ...
... (difference in y)/(difference in x) = (1-2)/(3-0) = -1/3 . . . . . matches choice A
The equation of the line is ...
... y = -1/3x + 2 . . . . . matches answer choice A
Remark
This question likely should be done before the other one. What you are trying to do is give C a value. So you need to remember that C is always part of an indefinite integral.
y =
y = sin(x) - cos(x) + C
y(π) = sin(π) - cos(π) + C = 0
y(π) = 0 -(-1) + C = 0
y(π) = 1 + C = 0
C = - 1
y = sin(x) - cos(x) - 1 <<<<< Answer
Problem Two
Remember that
y( - e^3 ) = ln(|x|) + C = 0
y(-e^3) = ln(|-e^3|) + C = 0
y(-e^3) = 3 + C = 0
3 + C = 0
C = - 3
y = ln(|x|) - 3 <<<< Answer
This question likely should be done before the other one. What you are trying to do is give C a value. So you need to remember that C is always part of an indefinite integral.
y =
y = sin(x) - cos(x) + C
y(π) = sin(π) - cos(π) + C = 0
y(π) = 0 -(-1) + C = 0
y(π) = 1 + C = 0
C = - 1
y = sin(x) - cos(x) - 1 <<<<< Answer
Problem Two
Remember that
y( - e^3 ) = ln(|x|) + C = 0
y(-e^3) = ln(|-e^3|) + C = 0
y(-e^3) = 3 + C = 0
3 + C = 0
C = - 3
y = ln(|x|) - 3 <<<< Answer