Solve for x. -4log2(5x)=-12

Mathematics

2 answers:

ivann1987 [24]3 years ago

6 0

-4log₂(5x)=-12

log₂(5x) = 3

5x = 2³ =8

x = 8/5 = 1.6

yanalaym [24]3 years ago

5 0

X=1.6

promise that's the right answer its just too much work to write the steps out(got my own stuff going on but I know an app that'll solve it for you. x and all, it won't let me type the name but the best I can say is two words. first word what subject is this English, history, mm..

the second word, show me the (blank.)
get out of my (blank.)
no (blank) man

You might be interested in

PLEASE HELP ASAP, I WILL GIVE BRAINLESSLY ANSWER <br> SHOW WORK PLEASE

zhannawk [14.2K]

Answer:

C. $N(t)=150\cdot 3^t$

Step-by-step explanation:

You are given the exponential function $n(t)=ab^t.$

From the table, $N(t)=150$ at $t=0,$ thus

$N(0)=a\cdot b^0\\ \\150=a\cdot 1\ [\text{ because }b^0=1]$

Also $N(t)=450$ at $t=1,$ thus

$N(1)=a\cdot b^1=a\cdot b.$

Since $a=150,$ substitute it into the second equation

$450=150\cdot b\\ \\b=\dfrac{450}{150}\\ \\b=3$

and the expression for the exponential function is

$N(t)=150\cdot 3^t$

5 0

3 years ago

If the money and interest are left in the bank how much is the total accumulated savings at the end of the second year for a sav

Mekhanik [1.2K]

$\qquad \textit{Compound Interest Earned Amount}\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\qquad 
\begin{cases}
A=\textit{current amount}\\
P=\textit{original amount deposited}\to &\$3,500\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=\textit{times it compounds per year}\to &1\\
t=years\to &2
\end{cases}
\\ \quad \\
A=3500\left(1+\frac{0.08}{1}\right)^{1\cdot 2}\implies 3500(1.08^2)$