You are looking for the average. To find the average, one adds all terms and divides by the number of terms. ((1/2)+(5/6))/2 ((3/6)+(5/6))/2 (8/6)/2 (4/6) (2/3) The answer is B) 2/3.
Well you are given the equation so let's plug in for kaylib and see how many miles she can see distance = sqrt [(3 * height) / 2] d = sqrt [(3 *48) / 2] d = sqrt (144 / 2) d = sqrt (72) d = sqrt (3 * 3 * 2 * 2 * 2) d = 6 * sqrt (2)
You you did not list Addisons height but I will say she is at x feet above sea level. we plug in x for height: d = sqrt [(3x) / 2]
It it says how much farther for Addison which means she can see farther. to find difference we just subtract kaylibs distance from Addison. so: sqrt [(3x) / 2] - 6 * sqrt (2)
plug in your x and use a calculator to get a decimal approximation
