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3 years ago

Can 10, 11, 2 be measures of the sides of a triangle

Mathematics

1 answer:

inessss [21]3 years ago

3 0

Answer:

Yes

Step-by-step explanation:

The Triangle Inequality Theorem says the sum of any two side lengths of a triangle has to be greater than the third side.

With the measures of 10, 11, and 2, this follows the theorem.

For example, 10 + 11 is 21, which is greater than 2.

11 + 2 is 13, which is greater than 10.

This works for all the combinations, so 10, 11, and 2 can be the side lengths.

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FrozenT [24]

4 ants = 24 legs 2 spiders = 16 legs
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3 years ago

5. 3x + 5y + 5z =1<br> x - 2y = 5<br> 2x + 4y = 11

lilavasa [31]

Answer:

see explanation

Step-by-step explanation:

Given the 3 equations

3x + 5y + 5z = 1 → (1)

x - 2y = 5 → (2)

2x + 4y = 11 → (3)

Use (2) and (3) to solve for x and y

Multiply (2) by 2

2x - 4y = 10 → (4)

Add (3) and (4) term by term

4x = 21 ( divide both sides by 4 )

x = $\frac{21}{4\\}$

Substitute this value of x into (3)

2 × $\frac{21}{4\\}$ + 4y = 11

$\frac{21}{2\\}$ + 4y = 11 ( subtract $\frac{21}{2\\}$ from both sides )

4y = $\frac{1}{2}$ ( divide both sides by 4 )

y = $\frac{1}{8\\}$

Substitute the values of x and y into (1) and solve for z

3 × $\frac{21}{4\\}$ + 5 × $\frac{1}{8\\}$ + 5z = 1

$\frac{63}{4}$ + $\frac{5}{8}$ + 5z = 1

$\frac{131}{8}$ + 5z = 1 ( subtract $\frac{131}{8}$ from both sides )

5z = - $\frac{123}{8}$ ( divide both sides by 5 )

z = - $\frac{123}{40}$

Solution is

x = $\frac{21}{4\\}$ , y = $\frac{1}{8\\}$ , z = - $\frac{123}{40}$

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3 years ago

Determine the length of JK

wlad13 [49]

The length of JK rounded to the nearest hundredth is 4.72

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3 years ago

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Step-by-step explanation:

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50 pts, trigonometry

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cos(0) = adjacent/hypotenuse = sqrt21/5

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sec(0) = hypotenuse/adjacent = 5sqrt21/21

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3 years ago

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