Answer:
(0, -3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
6x - 5y = 15
x = y + 3
<u>Step 2: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 6(y + 3) - 5y = 15
- Distribute 6: 6y + 18 - 5y = 15
- Combine like terms: y + 18 = 15
- [Subtraction Property of Equality] Subtract 18 on both sides: y = -3
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define original equation: x = y + 3
- Substitute in <em>y</em>: x = -3 + 3
- Add: x = 0
Answer:
The first one is ur answer
Step-by-step explanation:
Answer:
he has 10 type of each coin
Step-by-step explanation:
Total number of cents in possession is calculated as;
= 25 + 10 + 5
= 40 cent
Total amount in possession = $4
= 400 cent
Since he has equal number of each cent, let this equal number be "y";
40cent (y) = 400cent
40y = 400
divide both sides by 40

Therefore, he has 10 type of each coin
Since it decreased by 5 do 5 divided by 30 and you get the answer to be 16%