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3 years ago

PLEASE HELP ITS A PICTURE!!!!!!!!!!!!!!!

Mathematics

2 answers:

ss7ja [257]3 years ago

4 0

I say it was The Parthenon

Anna35 [415]3 years ago

4 0

The Correct And Most Logical Answer would be D) Hagia Sophia

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I need help understanding this. SO please help and give explanation

NikAS [45]

So my understanding from this you have to make it y = mx + b so m stands for the slope there’s different ways to find it as shown in the first picture. I’ll try to make another comment since this only lets me take one picture at a time.

5 0

3 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a

Alexandra [31]

To find where on the hill the canonball lands
So 0.15x = 2 + 0.12x - 0.002x^2
Taking the LHS expression to the right and rearranging we have -0.002x^2 + 0.12x -
0.15x + 2 = 0.
So we have -0.002x^2 - 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x^2 + 0.03x -2 = 0.
This is a quadratic eqn with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25. The second solution y = 0.15 * 25 = 3.75

8 0

3 years ago

A line goes through the origin and the point (6, 14). The point (2, y) is also on the line. Calculate y and justify that your va

guajiro [1.7K]

Answer:

Step-by-step explanation:

The key here is knowing that the equation of the line that passes through these points is same

Thus having (6,14) and (0,0), the slope is as follows;

m = y2-y1/x2-x1 = 0-14/0-6 = -14/-6 = 7/3

Now we can use this slope here to get the value of y in the question

All we need to do is tie write the equation of the line for between the points (6,14) and (2,y)

That would be;

7/3 = y-14/1-6

7/3 = y-14/-5

cross multiply;

-35 = 3(y-14)

-35 = -3y + 42

-3y = -35-42

-3y= -77

y = -77/3

y = 77/3

3 0

3 years ago

a gym teacher has a large canvas bag that contains 8 tennis balls, 2 volleyballs, 1 basketball, 3 baseballs, and 5 footballs. if

Serga [27]

Answer:

Step-by-step explanation:

5+1+3+8+2=19

3/19 = 16%

6 0

2 years ago