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vlabodo [156]
3 years ago
9

Machine machine with 140 gallon capacity needs to be filled with water/glycol mixture. Someone has already pump 50 gallons of 60

% glycol blend into the machine. How much more glycol must you add an order to get a 50% concentration?
Mathematics
1 answer:
9966 [12]3 years ago
6 0

Answer:

40 gal

Step-by-step explanation:

The capacity of the machine is 140 gallons, and it must be filled.

In a 50% glycol solution, the amount of glycol in 140 gallons of solution is

50% * 140 gallons = 70 gallons.

Once the machine is full with 140 gallons of 50% glycol solution, it will have 70 gallons of glycol.

The machine now has 50 gallons of 60% glycol solution.

60% * 50 gallons = 30 gallons

The machine has now 30 gallons of glycol.

70 gal - 30 gal = 40 gal

You must add another 40 gallons of glycol.

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What is the slope of a line perpendicular to<br><br> y =3/4 x+2
Irina18 [472]

Answer:

-3/4 slope

Step-by-step explanation:

y = 3/4 x +2 has a slope of 3/4

Perpendicular lines intersect.

So the slope of the perpendicular line must be opposite.

6 0
3 years ago
The weights of college football players are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds
Feliz [49]

Answer:

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 200, \sigma = 50

Find the probability that he weighs between 170 and 220 pounds.

This is the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 170.

X = 220

Z = \frac{X - \mu}{\sigma}

Z = \frac{220 - 200}{50}

Z = 0.4

Z = 0.4 has a pvalue of 0.6554

X = 170

Z = \frac{X - \mu}{\sigma}

Z = \frac{170 - 200}{50}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.6554 - 0.2743 = 0.3811

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

6 0
4 years ago
Is 1.994 greater or lesser than 1.493
just olya [345]

Answer:

greater than

Step-by-step explanation:

1.994 is closer to 2 than 1.493 so it is greater!

5 0
4 years ago
Read 2 more answers
Consider the following three expressions. To be the same what would P, Q, and R have to be
lidiya [134]

Step-by-step explanation:

Px^2+6x+1=x^2+x^2+Qx+1

P=2 and Q=6

Next, 3x^2-5-(x^2-6x+R/2)=2x^2+6x+1

2x^2-5-R/2+6x=x^2+6x+1

-5-R/2=6, R=-22

6 0
3 years ago
The senior classes at High School A and High School B planned separate trips to the indoor
Mazyrski [523]

Answer:

The number of students in each <u>van are 7</u> and number of students in each <u>bus are 23.</u>

Step-by-step explanation:

Let the number of students in each van be 'x' and number of students in each bus be 'y'.

Given:

<u>High School A:</u>

Number of students = 132

Number of buses = 3

Number of vans = 9

As per question,

9x+3y=132-------1

<u>High School B:</u>

Number of students = 205

Number of buses = 8

Number of vans = 3

As per question,

3x+8y=205-------2

Multiplying equation (2) by -3 and adding the result to equation (1), we get:

-3(3x+8y)=-3(205)\\-9x-24y=-615

-9x-24y=-615\\9x+3y=132\\---------\\-21y=-483\\y=\frac{-483}{-21}=23

Now, plug in 23 for 'y' in equation (1) and solve for 'x'. This gives,

9x+3(23)=132\\9x+69=132\\9x=132-69\\9x=63\\x=\frac{63}{9}=7

Therefore, the number of students in each van are 7 and number of students in each bus are 23

7 0
3 years ago
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