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Leokris [45]
3 years ago
11

PLEASE ANSWER QUICKLY

Mathematics
2 answers:
GaryK [48]3 years ago
8 0
We have that
<span>1/4 x + 2/3 y = 5 ----> multiply by 12 both sides---> 3x+8y=60
1/2 x + 3/2 y = 11---> multiply by 2 both sides----> x+3y=22

therefore

the answer is the option
</span><span>B. 3x + 8y = 60 ; x + 3y = 22</span>
elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

first one!

Step-by-step explanation:

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5 - ( m - 4 ) = 2m + 3 ( m -1 )
Leni [432]

Answer:

m=2

Step-by-step explanation:

8 0
2 years ago
PLZ HELP!!!!!!!!!!!!!!!
lara [203]
It’s 56 UwU


That’s your answer
5 0
3 years ago
Let Y be a random variable with a density function given by
Neporo4naja [7]

From the given density function we find the distribution function,

F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y

(a)

F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)

\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1

\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}

(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2

\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}

(c)

F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3

\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}

5 0
3 years ago
Can someone please help me with the question, a/4 = 15/12 a=?
malfutka [58]

Answer:

a = 5

Step-by-step explanation:

a/4 = 15/12

We can use cross products to solve

a* 12 = 4*15

12a = 60

Divide each side by 12

12a/12 = 60/12

a =5

7 0
2 years ago
Read 2 more answers
15n + 24 - 4(n - 3) + 6 - 2n = 105
elena55 [62]

Just trying to win the CONTEST BUT GOOOOD LUCK

7 0
3 years ago
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