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KonstantinChe [14]
4 years ago
12

A quadrilateral is shown below. What is the slope of line segment R¯¯S¯¯? (Type numerical answer only)

Mathematics
1 answer:
frutty [35]4 years ago
3 0
Slope, m, is \frac{rise}{run}

rise = y2-y1 = 5
run = x2-x1 = 1

so m = 5/1 or just 5
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Which define a right triangle?
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Answer:

no

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Step-by-step explanation:

---------------------

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3 years ago
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8 0
3 years ago
Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $29
il63 [147K]
For this problem, you have to come up with two equations, one for each plan, and set them equal to each other to solve for how many minutes <span>of calls when the costs of the two plans are equal. Let's call the number of minutes "x." Remember the equation for slope-intersect form is:
</span>y=mx+b
<span>And we're trying to put in values for m and b. 

So the first plan has a </span>$29 monthly fee and charges an additional $0.09 per minute. The $29 monthly fee will be our "b" in our slope-intersect equation because it won't be affected by our minutes "x."  That means 0.09 is our "m" value because it will change with "x." So our equation for plan 1 is:
y=0.09x+29

The second plan <span>has no monthly fee but charges 0.13 for each minute of calls. Because there is no monthly fee, there is no "b" this time. "m" will be 0.13. So our equation for plan 2 is"
</span>y=0.13x

Now we set our two equations equal to each other. "y" in the equation stands for the total cost of the plan. If the total costs are equal, then they have to be the same number, so we can put one of the equations for "y" into the other equation and solve for "x," our number of minutes:
0.13x = 0.09x+29 \\ 0.04x = 29 \\ x = 725 \: minutes

8 0
3 years ago
A process manufactures ball bearings with diameters that are normally distributed with mean 25.1 mm and standard deviation 0.08
marta [7]

Answer:

(a) The proportion of the diameters are less than 25.0 mm is 0.1056.

(b) The 10th percentile of the diameters is 24.99 mm.

(c) The ball bearing that has a diameter of 25.2 mm is at the 84th percentile.

(d) The proportion of the ball bearings meeting the specification is 0.8881.

Step-by-step explanation:

Let <em>X</em> = diameters of ball bearings.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 25.1 mm and standard deviation, <em>σ</em> = 0.08 mm.

To compute the probability of a Normally distributed random variable we need to first convert the raw scores to <em>z</em>-scores as follows:

<em>z</em> = (X - μ) ÷ σ

(a)

Compute the probability of <em>X</em> < 25.0 mm as follows:

P (X < 25.0) = P ((X - μ)/σ < (25.0-25.1)/0.08)

                    = P (Z < -1.25)

                    = 1 - P (Z < 1.25)

                    = 1 - 0.8944

                    = 0.1056

*Use a <em>z</em>-table for the probability.

Thus, the proportion of the diameters are less than 25.0 mm is 0.1056.

(b)

The 10th percentile implies that, P (X < x) = 0.10.

Compute the 10th percentile of the diameters as follows:

P (X < x) = 0.10

P ((X - μ)/σ < (x-25.1)/0.08) = 0.10

P (Z < z) = 0.10

<em>z</em> = -1.282

The value of <em>x</em> is:

z = (x - 25.1)/0.08

-1.282 = (x - 25.1)/0.08

x = 25.1 - (1.282 × 0.08)

  = 24.99744

  ≈ 24.99

Thus, the 10th percentile of the diameters is 24.99 mm.

(c)

Compute the value of P (X < 25.2) as follows:

P (X < 25.2) = P ((X - μ)/σ < (25.2-25.1)/0.08)

                    = P (Z < 1.25)

                    = 0.8944

                    ≈ 0.84

*Use a <em>z</em>-table for the probability.

Thus, the ball bearing that has a diameter of 25.2 mm is at the 84th percentile.

(d)

Compute the value of P (25.0 < X < 25.3) as follows:

P (25.0 < X < 25.3) = P ((25.0-25.1)/0.08 < (X - μ)/σ < (25.3-25.1)/0.08)

                    = P (-1.25 < Z < 2.50)

                    = P (Z < 2.50) - P (Z < -1.25)

                    = 0.99379 - 0.10565

                    = 0.88814

                    ≈ 0.8881

*Use a <em>z</em>-table for the probability.

Thus, the proportion of the ball bearings meeting the specification is 0.8881.

4 0
3 years ago
Is 13812 divisible by 3
In-s [12.5K]
Yes it would be 4604
hope this is helpful to you! :D
8 0
4 years ago
Read 2 more answers
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