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Romashka-Z-Leto [24]
3 years ago
14

*Please Help!*

Mathematics
1 answer:
trapecia [35]3 years ago
8 0

Answer:

The volume of water that will fill the spa tub is 5.9 cubic meters.

Step-by-step explanation:

Volume of water that would fill the spa tub = volume of semi sphere - (volume of the first cylinder + volume of the second cylinder)

i. volume of first cylinder = \pir^{2}h

where r is the radius and h is the height of the cylinder.

r = \frac{0.75}{2} = \frac{3}{8}

 = 0.375 m

h = 0.80 m

volume of the first cylinder = \frac{22}{7} x (\frac{3}{8} )^{2} x 0.8

                                        = 0.3536 cubic meters

ii. volume of the cylinder underneath = \pir^{2}h

r = \frac{1.25}{2} = \frac{5}{8}

 = 0.625

h = 0.70 m

volume of the cylinder underneath = \frac{22}{7} x (\frac{5}{8}) ^{2} x 0.7

                                                      = 0.8594 cubic meters

iii. volume of the semi sphere = \frac{2}{3} \pir^{3}

where r is the radius = 1.5 m

volume of the semi sphere = \frac{2}{3} x \frac{22}{7} x (1.5)^{3}

                                             = 7.0714 cubic meters

Thus,

volume of the water to fill the spa tub = 7.0714 - (0.3536 + 0.8594)

                                                     = 5.8584

The volume of water that will fill the spa tub is 5.9 cubic meters.

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Answer:

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Step-by-step explanation:

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F(X,Y)(x,y)=P(X≤x,Y≤y)=P(s(X)≤s(x),t(Y)≥t(y))

The last step is obtained by applying the functions s and t since s preserves order and t reverses it.

This can be further transformed into

F(X,Y)(x,y)=1−P(s(X)≤s(x),t(Y)≤t(y))=1−F(s(X),t(Y))(s(x),t(y))

Since our random variables are continuous, we assume that the difference between t(Y)≤t(y) and t(Y)<t(y)) is just a set of zero measure.

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F(X,Y)(F−1X(a),F−1Y(b))=1−F(s(X),t(Y))(s(F−1X(a)),t(F−1Y(b)))

The left hand side is the copula C(X,Y), the right hand side still needs some work.

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Fs(X)(s(F−1X(a)))=P(s(X)≤s(F−1X(a)))=P(X≤F−1X(a))=FX(F−1X(a))=a

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Ft(Y)(s(F−1Y(b)))=P(t(Y)≤t(F−1Y(b)))=P(Y≥F−1Y(b))=1−FY(F−1Y(b))=1−b

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